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joja [24]
3 years ago
5

I need to know what z = xm + y, for x

Mathematics
2 answers:
hram777 [196]3 years ago
7 0

Answer: xm + y = z  xm = z - y  x = (z - y)/(m)

Step-by-step explanation: hope this helped :)

Anna007 [38]3 years ago
7 0

Answer:

x = (z - y) / m

Step-by-step explanation:

z = xm + y

xm + y = z

xm = z - y

x = (z - y) / m

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Which sequence can be generated from the formula f(x + 1) = One-half(f(x))?
AlekseyPX

Answer:

x, StartFraction x Over 2 EndFraction, StartFraction x Over 4 EndFraction, StartFraction x Over 8 EndFraction, ellipsis

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP URGENT! 25 POINTS
Reika [66]

Answer:

56°

Step-by-step explanation:

a straight line is 180° and 124° subtracted from 180° is 56°

8 0
3 years ago
A man bought 500 mangoes and found 1/4 of them rotten .If he sold the rest of mangoes at 3.36 each making 12% profit ,what was t
suter [353]

Answer:

<em>The cost price of each mango was $3</em>

Step-by-step explanation:

The man bought 500 mangoes, but 1/4 of them were rotten. There were 1/4*500 = 125 rotten mangoes, thus the number of mangoes he sold is

500 - 125 = 375 mangoes

Selling them at $3.36 each, he had revenue of

375*3.36=$1,260

That amount includes the 12% profit, that is, it's 112% of the cost price, thus the cost price of all mangoes is

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The price of each mango was $1,125 / 375 = $3

The cost price of each mango was $3

4 0
3 years ago
Sara has 20 sweets. She has 12 liquorice sweets, 5 mint sweets and 3 humbugs. Sarah is going to take, at random, two sweets Work
Debora [2.8K]

Answer:

111 / 190

Step-by-step explanation:

Let us first compute the probability of picking 2 of each sweet. Take liquorice as the first example. There are 12 / 20 liquorice now, but after picking 1 there will be 11 / 19 left. Thus the probability of getting two liquorice is demonstrated below;

12 / 20 * 11 / 19 = \frac{33}{95},\\Probability of Drawing 2 Liquorice = \frac{33}{95}

Apply this same concept to each of the other sweets;

5 / 20 * 4 / 19 = \frac{1}{19},\\Probability of Drawing 2 Mint Sweets = 1 / 19\\\\3 / 20 * 2 / 19 = \frac{3}{190},\\Probability of Drawing 2 Humbugs = 3 / 190

Now add these probabilities together to work out the probability of drawing 2 of the same sweets, and subtract this from 1 to get the probability of not drawing 2 of the same sweets;

33 / 95 + 1 / 19 + 3 / 190 = \frac{79}{190},\\1 - \frac{79}{190} = \frac{111}{190}\\\\

The probability that the two sweets will not be the same type of sweet =

111 / 190

3 0
3 years ago
Square root 32 multiplied by square root 24
Svetlanka [38]

Answer:

16 times the square root of 3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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