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svetoff [14.1K]
3 years ago
6

Hello I’m trying to solve this problem I just don’t know how to do it.

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
3 0

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

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Answer:

302

Step-by-step explanation:

420(grams per sec)x60(seconds in a min) = 25,200(grams per min)

25,200x60(min in an hour) = 1,512,000(grams an hour)

1,512,000/1,000(grams in a kilogram) = 1,512 (kilograms per hour)

1,512/20 (size of bag) = 75.6 (bags filled per hour)

75.6x4(hours elapsed asked by the question) = 302 bags completly filled in 4 hours

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2. Barbara’s Catering Company makes the best fruit salad despite using only four ingredients. They use four apples for every man
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4 years ago
A cosmetics company makes small, cylindrical bars of soap, and wraps them in plastic prior to packing them in boxes for shipping
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a. In order to determine how much soap material is used for each bar of soap, consider that the shape of the bar is a cylinder, then, use the folowing formula for the volume of a cylinder:

V = π r² h

where r is the radius of the base and h is the height.

The diameter is 5 cm, then, the radius is r = d/2 = 5 cm/2 = 2.5 cm

The height is h = 2 cm

replace the previous values into the formula for V:

V = (3.14)(2.5 cm)²(2 cm)

V = 39.25 cm³

Hence, 39.25 cm³ of soap material is used to make each bar.

b. In this case it is necessary to calculate the suface area of the plastic used. As before, take into account that the bar has a cylindrical shape. Then, use the following formula for the surface area of a cylinder:

S = 2πr² + 2πrh

replace the values of the parameters to find S:

S = 2π(2.5 cm)² + 2π(2.5cm)(2cm)

S = 70.68 cm²

Hence, 70.68 cm² of plastic is required to wrap each bar

c. Take into account that the soap must be stacked no more than 5 bars high, and that the company wants to ship a minimum of 60 bars.

If there are 5 bars high x 3 bars length, in one face of the box you have 15 bars. Moreover, if there are 4 bars width, then, you have a total of 15x4 = 60 bars in one box, which is what the company wants.

The height of the box is given by 5 times the height of one bar (because there are 5 bars high). The length is given by 3 times the diameter of one bar and the width of the box is given by 4 times the diameter of one bar:

height of the box = 5(2 cm) = 10 cm

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width of the box = 4(5 cm) = 20 cm

d. First, calculate the volume of the box, as follow:

V = h x l x w = (10 cm)(15 cm)(20 cm) = 3,000 cm³

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Answer:

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As the sample size is 40 and confidence interval is 99%. Therefore the value of t_{n-1}=2.70.

Now, substitute the respective values in the above formula.

35.8\pm 2.70\times \frac{2.5}{\sqrt{40}}

35.8\pm 2.70\times \frac{2.5}{6.32}

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