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Arada [10]
3 years ago
10

Solve the system using the elimination method. write solution as a orders pair.

Mathematics
2 answers:
Zigmanuir [339]3 years ago
8 0

Answer:

4x-2y=0

Step-by-step explanation:

Ok

so you need to subtract

(3x+2y=22)-(-x+4y=22)

Use distributive property and take away parenthesis

3x+2y=22+x-4y=-22

----------------------------

3x+2y=22

x-4y=-22

------------------------------

4x-2y=0

Brainliest Please

kicyunya [14]3 years ago
6 0

Answer:

<em>( </em>\frac{22}{7}<em> , </em>\frac{44}{7}<em> ) </em>

Step-by-step explanation:

3x + 2y = 22 ....... <em>(1)</em>

- x+ 4y = 22 ........ <em>(2)</em>

3 × <em>(2)</em> + <em>(1)</em>

<u><em>(3x - 3x)</em></u> + (2y + 12y) = 22 + 66 ( variable "x" is eliminated )

14y = 88

y = \frac{44}{7}

- x + 4( \frac{44}{7} ) = 22

x = \frac{176}{7} - \frac{154}{7} = \frac{22}{7}

<em>( </em>\frac{22}{7}<em> , </em>\frac{44}{7}<em> )</em>

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1. 11 1/6 =? 2. 2 9/10 =? 3. - 4/12 =? Please help me
Jobisdone [24]

Answer:

1.Exact Form: 67/6

Decimal Form: 11.167

Mixed Number Form: 11 1/6

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4 0
3 years ago
Which values of a and b make the following equation true?  a = 11, b = 7 a = 11, b = 10 a = 28, b = 7 a = 28, b = 10
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6 0
3 years ago
Read 2 more answers
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0
3 years ago
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