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3 years ago

8° below zero in the winter

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

Answer:

negative

Step-by-step explanation:

romanna [79]3 years ago

7 0

Negative (example: -9)

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What is the slope of the line?

Katyanochek1 [597]

Answer:

Step-by-step explanation:

slope (k) is the rise over run of the line

a way of finding the slope if you have two dots of the line is:

$k \: = \frac{y2 - y2}{x2 - x2}$

here the dots that belong to the line that you can most easily see are:

A(-6,0)

B(0,6)

by inserting the values into the euquation you get:

$\frac{6 - 0}{0 - ( - 6)} = \frac{6}{6} = 1$

good luck with your maths solving

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2 years ago

What is 110% of 90 as a fraction

Vlad1618 [11]

110% of 90 is:
90*1.10 = 99

5 0

3 years ago

Read 2 more answers

5y+5x+3=2 solve for y

denpristay [2]

Answer:y=-1/5-x

Step-by-step explanation:

3 0

3 years ago

Please tell me the answer as simple as you can

dalvyx [7]

Answer:

9 lol

Step-by-step explanation:

sun of 4 and 5 is 9

difference between 8 and 7 is 9

multiply 9 by 1

5 0

3 years ago

Complete the assignment on a separate sheet of paper Please attach pictures of your work.

Irina18 [472]

Answer:

TO FIND :-

Length of all missing sides.

FORMULAES TO KNOW BEFORE SOLVING :-

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

SOLUTION :-

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

5 0

3 years ago

8° below zero in the winter ​

8° below zero in the winter