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3 years ago

PLZ HELP ASAP

Mathematics

1 answer:

lys-0071 [83]3 years ago

3 0

Answer:

Each kids weight in a chart

Step-by-step explanation:

I chose this because its the most organized way of doing that

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Could someone help me please please

Vera_Pavlovna [14]

this is what you get while graphing the equation ! hopes this helps with your answer !

5 0

2 years ago

if £5000 Is placed into a bank account that pays 2% compound interest per year, how much will be in the account after two years

timurjin [86]

Answer:

£5200

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 2%/100 = 0.02 per year,

then, solving our equation

I = 5000 × 0.02 × 2 = 200

I = £ 200.00

The simple interest accumulated

on a principal of £ 5,000.00

at a rate of 2% per year

for 2 years is £ 200.00.

5 0

2 years ago

How many sides do a square have

loris [4]

A square has four sides. Hope this helps you.

4 0

3 years ago

Read 2 more answers

Find the volume of the triangular prism.

goldfiish [28.3K]

Answer:

V = 31.5 in ^3

Step-by-step explanation:

The volume is Bh

The base is the triangle

B = 1/2 (7) *2

B = 7 in^2

Now find the volume

V = 7* 4.5

V = 31.5 in ^3

5 0

3 years ago

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

8 0

3 years ago