Answer:
<em>Part A: </em>
<em>c = 1.15p</em>
<em>c(2) = $2.30</em>
<em>Part B: </em>
<em>c = 0.90p</em>
Part B:
Step-by-step explanation:
<u>Linear Models</u>
Candy's Sweets Company charges $1.15 per pound to ship candy. This represents a proportional relationship between the pounds of candy and the cost.
Part A: If each pound costs $1.15, then p pounds cost $1.15p. Then the equation of the cost c is:
c = 1.15p
The cost of shipping p=2 pounds of candy is:
c = 1.15*2 = 2.30
c = $2.30
Part B: When the company reduces the cost by $0.25 per pound, the new unit cost is $1.15 - $0.25 = $0.90 per pound.
The new equation to determine the total cost for p pounds of candy is:
c = 0.90p
Answer:1/2,-3/2,-3/8
Step-by-step explanation:
We want to isolate T. So, we will divided IR from both sides, so our equation is now
P/IR=T
There ya go!
Answer: 1. ∠A= 80.75° 2. 41.79 ![cm^2](https://tex.z-dn.net/?f=cm%5E2)
Step-by-step explanation:
Since, According to the sines low,
![\frac{sin A}{CB} = \frac{sin C}{AB}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20A%7D%7BCB%7D%20%3D%20%5Cfrac%7Bsin%20C%7D%7BAB%7D)
Here, CB= 4.1 cm, AB = 3.3 and ∠ C = 52.6°
![\frac{sin A}{4.1} = \frac{sin 52.6}{3.3}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20A%7D%7B4.1%7D%20%3D%20%5Cfrac%7Bsin%2052.6%7D%7B3.3%7D)
⇒ ![sin A = 4.1\times\frac{sin 52.6}{3.3}](https://tex.z-dn.net/?f=sin%20A%20%3D%204.1%5Ctimes%5Cfrac%7Bsin%2052.6%7D%7B3.3%7D)
⇒ ![sin A =0.98699998308](https://tex.z-dn.net/?f=sin%20A%20%3D0.98699998308)
⇒ A = 80.75°
2. Since, the area of the given figure = Area of the rectangle having dimension 8.3 × 4.2 + Area of the half square of radius 2.1
=34.86 + 6.93
= 41.79 square cm