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jeyben [28]
3 years ago
11

What is the standard form for the quadratic function?f(x) = (x – 3)2 + 5​

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

f(x)  = x² - 6x + 14

Step-by-step explanation:

Standard form is ax² + bx + c = 0 or f(x) = ax² + bx + c

So we are going to expand the equation and combine like terms:

f(x) = (x - 3)² + 5

f(x) = x² - 3x - 3x + 9 + 5

f(x) = x² - 6x + 9 + 5

f(x) = x² - 6x + 14

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We will write our equation in vertex form and then convert it into standard form.

Vertex for of parabola is y=a(x-h)^2+k, where point (h,k) represents vertex of parabola and a represents leading coefficient.

Since our parabola is downward opening so leading coefficient will be negative.

Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:

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