The complete question would be as follows:
700,000 tons of baking soda are produced per year. <span>How many kilograms of carbon dioxide are used per year to produce baking soda?
We calculate as follows:
</span><span>CO2(g) + NH3(aq) + NaCl(aq) + H2O -----> NaHCO3(s) + NH4Cl(aq)
</span>
700000 tons NaHCO3 ( 907.185 kg / 1 ton ) (<span>1 kmole NaHCO3 / 84.0 kg NaHCO3) x (1 kmole CO2 / 1 kmole NaHCO3) x (44.0 kg CO2 / 1 kmole) = 3x10^8 kg CO2
Hope this answers the question. Have a nice day.</span>
It represents a chemical change
Answer : The standard enthalpy of formation of methane is, -74.8 kJ/mole
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we will reverse the reaction 1, multiply reaction 3 by 2 then adding all the equations, we get :
(1) 
(2)
(3) 
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of methane is, -74.8 kJ/mole
Its known as covalently bonded atoms
First c<span>alculate the mole fraction of each substance:
acetone: 2,88 mol </span>÷ (2,88 mol + 1,45 mol) = 0,665.
cyclohexane: 1,45 ÷ (2,88 mol + 1,45 mol) = 0,335.
Raoult's Law:
P(total) = P(acetone) · χ(acetone) + P(cyclohexane) · χ(cyclohexane).
P(total) = 229,5 torr · 0,665 + 97,6 torr · 0,335.
P(total) = 185,3 torr.
χ for acetone: 229,5 torr · 0,665 ÷ 185,3 torr = 0,823.
χ for cyclohexane: 97,6 torr · 0,335 ÷ 185,3 torr = 0,177.
