Answer: Potassium Iodide, KI
Explanation:
Flame test colors:
Li+ = Crimson Red
Na+ = Bright Orange-Yellow
K+ = Lilac
Addition of nitric acid and silver nitrate (HNO3 and AgNO3),
Cl- = White precipitate
Br- = Creamy precipitate
I- = Yellow Precipitate
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Answer:
The answer is 17.03052. We assume you are converting between grams Ammonia and mole.
Answer:
The specific heat for the metal is 0.466 J/g°C.
Explanation:
Given,
Q = 1120 Joules
mass = 12 grams
T₁ = 100°C
T₂ = 300°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
ΔT = T₂ - T₁ = 300°C - 100°C = 200°C
Substituting values,
1120 = (12)(200)(Cp)
Cp = 0.466 J/g°C.
Therefore, specific heat of the metal is 0.466 J/g°C.
Answer:
Sunlight
Water
And carbon dioxide
Additional information :
6CO2 + 6H2O → C6H12O6 + 6O2
