Answer:
The acetylene must be fill at 315 atm.
Explanation:
Given data:
Pressure of oxygen =P₁= 135 atm
Volume of oxygen = V₁=7.00 L
Volume of acetylene = V₂=3.00 L
Pressure of acetylene =P₂= ?
Solution:
According to Boyle's law
P₁V₁ = P₂V₂
P₂ = P₁V₁/V₂
P₂ = 135 atm × 7.0 L / 3.00 L
P₂ = 945 atm. L/ 3.00 L
P₂ = 315 atm
The acetylene must be fill at 315 atm.
Carboxylic acid...........
The molarity of KCl solution made by diluting 75.0 ml of a 0.200M solution to a final volume of 100ml is calculated using the below formula
M1V1=M2V2
M1=0.200 M
V1= 75.0 Ml
V2= 100 ml
M2=?
by making M2 the formula of the subject M2 =M1V1/V2
=75.0 ml x0.200 M/100 Ml = 0.15 M
Answer:
Mass of KNO3 in the original mix is 146.954 g
Explanation:
mass of 
in original 254.5 mixture.
moles of 
moles of
= 0.2926 mol of BaSO4
Therefore,
0.2926 mol of BaCl2,
mass of 
= 60.92 g
the AgCl moles 
= 1.3891 mol of AgCl
note that, the Cl- derive from both, 
so
mole of Cl- f NaCl 
mol of Cl-
mol of NaCl = 0.8039 moles
then
KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3
Mass of KNO3 in the original mix is 146.954 g
Answer:
30%
Explanation:
As the formula for finding concentration
= (mass of solute/mass of solution)×100
= (30/100)×100
= 0.3×100
= 30%
