Answer:
Mass is the amount of matter in an object.
Weight is how much an object weighs.
Hope this helps!
Answer:
we know, at STP ( standard temperature and pressure).
we know, volume of 1 mole of gas = 22.4L
weight of 1 Litre of hydrogen gas = 0.09g
so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.
similarly,
weight of 2L of a gas = 2.88gm
so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g
hence, molecular weight of the gas = 32.256g
vapor density = molecular weight/2
= 32.256/2 = 16.128g
hence, vapor density of the gas is 16.128g.
Explanation:
Answer:
A reaction in which the oxidation state of one element increases and another decreases
Explanation:
Redox reaction means both oxidation and reduction take place in that reaction.
So when an element oxides its oxidation state increases and when an element reduces its oxidation state decrease.
Answer: Volume of CO2 is 89127 mL
Explanation: The reaction that takes place is: C2H2 + O2 --> CO2 + H2O
The amount of C2H2 that react allow us to predict the amount of CO2 that will be obtained
26g/1mol is molar mass of C2H2 and 2/4 is the molar relation between CO2 and C2H2 in this reaction. Canceling units, at the end mol of CO2 are obtained
Now with the moles of CO2 and the ideal gases equation is possible to calculate the volumen occupied by the gas.
PV = RnT where P: pressure, V: volume, R: ideal gas constant, n: moles and T: temperature expressed in K (add 273,15 to °C temperature: 37,4°C + 273,15 = 310,55K)
V= RnT/P
To express volume in mL multiply the L result by 1000 which equals 89127 mL
The mass number of element is 22.
The mass number is the sum of number of electrons/proton and number of neutron .
Mass number = number of proton/electron + number of neutrons
If an element with 11 neutrons, 11 protons, and 11 electrons then mass number is calculated as,
Mass number = number of proton/electron + number of neutrons
Mass number = 11 + 11 = 22
learn about element
brainly.com/question/14347616
#SPJ4
