I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

If we solve the first two equations for y squared, we have

And we can deduce

So that the third equation becomes

(we can't accept the negative root because negative lengths make no sense)
E+r=
(e=9)
r=1.50)
or 9+1.50=
I think
The given equation is an equation of a circle because it looks similar to the general equation of a circle.
<h3>What is the general equation of a circle?</h3>
The general equation of a circle is:
x² + y² +2gx + 2fy + c = 0...........eq1
Where (-g, -f) is the center of the circle.
c is a constant
Given equation is
3x² +6x + 3y²+7y+4 = 0
Let us take 3 as common
x² + 2x+y²+7/3y + 4/3 = 0
Let us rearrange the equation
x² + y²+2x +7/3y + 4/3 = 0...........eq2
Now look at eq1 and eq2
We got that eq2 is having a similar pattern as eq1.
Therefore, The given equation is an equation of a circle.
To get more about circle visit:
brainly.com/question/1506955