55 blue or red marbles,
55-22 = 33 blue marbles
bag1+bag2= 2525
bag1=.4
33/55=.6 blue marbles
bag 2=.6
so it is 40% that U choose bag 1
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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Answer:
Hi there!
Your answer is:
$72.45
Step-by-step explanation:
[28+ (28× .15) ] + [ 35 + (35× .15) ]
( 28+ 4.2) + (35 + 5.25)
32.2 + 40.25
72.45
Hope this helps
Answer:
f(x)= $70 - $1.5*x
Step-by-step explanation:
You know your friend spends $ 5 to enter the fair and $ 15 for food. So the total you spent is given by:
$5 + $15= $20
Knowing that the trips at the fair cost $ 1.50 per trip, and with x being the number of trips, then the cost after x trips will be:
$1.5*x
So the money spent after x rides can be expressed as:
$20 + $1.5*x
Knowing that your friend has $90 when he goes to the fair, to calculate the amount of money he has left after x rides, the amount taken to the fair and the amount spent is subtracted:
$90 - ($20 + $1.5*x)
$90 -$20 -$1.5*x
$70 - $1.5*x
By calling the function f(x) used to determine the amount of money left after x trips, you can finally express:
<u><em>f(x)= $70 - $1.5*x</em></u>
