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3 years ago

Please help on all three of these

Mathematics

1 answer:

Maslowich3 years ago

3 0

Answer:

$2) \: y = - 3x + 5 \\ 3) \: y = \frac{1}{4}x - 2$

Step-by-step explanation:

Remmeber:

$slope = \frac{rise}{run}$

I am unsure how to do number 4.

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I really need help I'm stuck on this question please help

vagabundo [1.1K]

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3 years ago

If u can answer these please do

enot [183]

Answer:

1) 8.5x10^8

2) 5.3x10^-3

3) 9.95x10^12

Step-by-step explanation:

Since they have the same exponents, you just add or subtract and leave the rest the same.

1) 8.5x10^8

2) 5.3x10^-3

3) 9.95x10^12

8 0

3 years ago

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In the first 120 miles over 240 mile journey a truck driver maintained an average speed of 50 mph what was his average featuring

Keith_Richards [23]

The correct answer is 70 MPH because when 50 and 70 are added together and divided by 2, you get 60.

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3 years ago

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Whats 35.78 rounded to the nearest whole second?

Kobotan [32]

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8 0

3 years ago

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A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par

lyudmila [28]

Answer:

$a(\frac{1}{5e})=5e$

Step-by-step explanation:

we are given equation for position function as

$s(t)=tln(5t)$

Since, we have to find acceleration

For finding acceleration , we will find second derivative

$s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)$

$=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t$

$=1\cdot \ln \left(5t\right)+\frac{1}{t}t$

$s'(t)=\ln \left(5t\right)+1$

now, we can find derivative again

$s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)$

$=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)$

$=\frac{1}{t}+0$

$a(t)=\frac{1}{t}$

Firstly, we will set velocity =0

and then we can solve for t

$v(t)=s'(t)=\ln \left(5t\right)+1=0$

we get

$t=\frac{1}{5e}$

now, we can plug that into acceleration

and we get

$a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}$

$a(\frac{1}{5e})=5e$

5 0

3 years ago