9514 1404 393
Answer:
- 13 ft
- (a) 1 second; (b) t = 0, t = 1/2
Step-by-step explanation:
<h3>1. </h3>
Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...
5² +(w -1)² = w²
w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms
26 = 2w . . . . . . . . . . . . add 2w
13 = w . . . . . . . . . . . . divide by 2
The length of the wire is 13 feet.
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<h3>2. </h3>
(a) When h = 0, the equation is ...
0 = -16t^2 +8t +8
Dividing by -8 puts this into standard form:
2t^2 -t -1 = 0
Factoring, we get ...
(2t +1)(t -1) = 0
The positive value of t that makes a factor zero is t = 1.
It will take 1 second for the gymnast to reach the ground.
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(b) When h = 8, the equation is ...
8 = -16t^2 +8t +8
Subtract 8 and divide by 8 to get ...
0 = -2t^2 +t
0 = t(1 -2t) . . . . factor out t
Values of t that make the factors zero are ...
t = 0
t = 1/2
The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.
Answer:
variation constant = k = 8
equation of variation : y = 8x
Step-by-step explanation:
Any relationship of variation can be written as y = kx
where k is the variation constant.
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Let the equationof relation between y and x be y =kx here as well
given
y = 16 when x = 2
substituting this value in the equation y = kx
16 = k*2
=> k = 16/2 = 8
Thus,
variation constant = k = 8
equation of variation : y = 8x
Answer:
MK
Step-by-step explanation:
ML is the short side of right triangle MLK. MJ is the hypotenuse of right triangle MKJ. This gives you a clue that the ratios of interest are the short side to the hypotenuse. All these right triangles are similar, so ...
ML/MK = MK/MJ . . . . . ratio of short side to hypotenuse is the same
ML·MJ = MK² . . . . . . . cross multiply
MK = √(ML·MJ) . . . . . the geometric mean of ML and MJ is MK
Log base 3 of 4 + log base 3 of 11= log base 3 of 4•11; Answers is 11