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katovenus [111]

3 years ago

5

Drag values to complete each equation. 95⋅9‐993 =? (94)3⋅9‐14 = ? options: 9 to the power of 7 9 to the power of negative 7 9 to

the power of negative 2 9 to the power of negative 1

1 answer:

Kazeer [188]3 years ago

8 0

Answer: yuhhhh

Step-by-step explanation: get in to it

sorry for doing this i need points

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-8x%2B16%20%7D%7Bx%5E%7B2%7D-7x%2B12%20%7D" id="TexFormula1" title="\frac

trapecia [35]

Answer:

$\frac{x - 4}{x - 3}$

Step-by-step explanation:

$\frac{ {x}^{2} - 8x + 16 }{ {x}^{2} - 7x + 12}$

Lets split the numerator and denominator.

$= > \frac{ {x}^{2} - 4x - 4x + 16}{ {x}^{2} - 3x - 4x + 12}$

Lets factorise the numerator and denominator.

$= > \frac{x(x - 4) - 4(x - 4)}{x(x - 3) - 4(x - 3)}$

$= > \frac{(x - 4)(x - 4)}{(x - 3)(x - 4)}$

Cancelling x - 4 from numerator and denominator ,

$= > \frac{x - 4}{x - 3}$

8 0

3 years ago

4/5, √9, -0.95, √32/8, 2.9, - √6 PLEASE order from least to greatest

Eva8 [605]

Answer:

-√6 -0.95 √32/8 4/5 2.9 √9

Step-by-step explanation:

4/5, √9, -0.95, √32/8, 2.9, - √6

4/5 = 0.8

√9 = 3

√32/8 = 4√2 / 8 = √2/2 = 0.707

-√6 = -2.449

-√6 -0.95 √32/8 4/5 2.9 √9

8 0

3 years ago

Paga No. Date: 6. When a discount of 25% is allowed on the marked price then the selling price will be 1425 .lf the marked price

SVETLANKA909090 [29]

Answer:

The percentage loss = 10.9375 %

Step-by-step explanation:

Let the cost price = x

Since the marked price is 18.75% above the cost price so the

Marked price = 1.1875 x

When a discount of 25% is allowed on the marked price , the selling price will be Rs. 1425

⇒ Marked price × 0.75 = 1425

⇒ Cost price × ( 1.1875 × 0.75 ) = 1425

⇒ Cost price × ( 0.890625 ) = 1425

⇒ Cost price = 1600

Selling price = 1425

So percentage loss = × 100

% Loss = × 100

% Loss = 10.9375 %

5 0

3 years ago

What is the next to numbers In the pattern 4.15,6.3,8.45

olganol [36]

Answer:

9.54

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the equation of line passing through points A (1, 3) and B (3, 7).

Sidana [21]

Solution:

To find the equation of line passing through points A (1, 3) and B (3, 7).

we know that, to derive the equation of a line we first need to calculate the slope of the line. Slope m of a line at points $(x_{1} ,y_{1})$ and $(x_{2}, y_{2})$ is given by - $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ .

Slope of the line at point A(1,3) and B(3,7)

$m=\frac{7-3}{3-1}$ .

$m=\frac{4}{2}$ .

$m=2$ .

Equation of a line using a point and a slope , $y-y_{1}= m(x-x_1)$

$y-3= 2(x-1)$

$y-3= 2x-2$

$y= 2x-2+3$

$y= 2x+1$

The equation of line passing through points A (1, 3) and B (3, 7) : $y= 2x+1$

4 0

3 years ago