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SCORPION-xisa [38]
3 years ago
14

Send the answer from 18 to 23 with process in copy​

Mathematics
1 answer:
viktelen [127]3 years ago
4 0

19. Perimeter of rectangle = 2(l + b)

l = 25m

b = 16m

Perimeter of rectangular park = 2 (25 + 16)

= 50 + 32

= 82m

Perimeter of square park = 82m

(given that, perimeter of rectangular and square park are equal)

Perimeter of square = 4a

4a = 82

a = 82/4

a = 20.5m

Area of square park = a²

= 20.5²

= 420.25m²

20. Perimeter of regular hexagon = 6a

a = 2.5

6a = 6 × 2.5

= 15cm

21. Perimeter of regular decagon = 10a

a = 8

10a = 10 × 8

= 80cm

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Given the function h(x) = 4x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
morpeh [17]
Section A) The AROC for Part A is 4.
            h(x) = 4 * 1. 4 is your answer.
Section B) The AROC for Part B is 1.
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Part A: (Above)

Part B: There is no greater average change, both X's AROC is 4.


A.R.O.C: (Average Rate of Change)

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6 0
4 years ago
ZA and B are supplementary angles.
yKpoI14uk [10]

Answer:

135°

Step-by-step explanation:

a supplementary angle is equal to 180°. since you already have the measure of ZA, all you need to do is subtract 45°, the measure of ZA, from 180°, the total measure of a supplementary angle, in order to figure out the measure of ZB.

180 - 45 = 135, therefore the measure of ZB = 135°.

5 0
3 years ago
A cargo plane flew roundtrip from Smithtown to Johnsville. It took one hour less time to get there than it did to get back. The
iren [92.7K]

Answer:

13 hours

Step-by-step explanation:

Average speed = Distance traveled / time taken

                   ⇒ Distance = Average speed × Time

                                     d = s × t

For the first trip;

Average speed = 280 mph

                          d₁ = 280t₁                    ------(1)

where;

d₁ is the distance covered to get to the destination

t₁ is the time taken to get to the destination

For the second trip;

Average speed = 240 mph

                           d₂= 240t₂                     ------(2)

where;

d₂ is the distance covered on the way back

t₂ is the time taken on the way back

The trip is the same distance to and fro. Therefore,

                           d₁ = d₂                              

Substituting the equation for d₁ and d₂

                          280t₁ = 240t₂              ------(3)

It took one hour less time to get there than it did to get back, then,

                                 t₁ = t₂ - 1

                                 t₂ = t₁ + 1                ------(4)

Substituting equation (4) into  equation (3)

                               280t₁ = 240(t₁ + 1)

                               280t₁ = 240t₁ + 240

                               280t₁ - 240t₁ = 240

                               40t₁ = 240

                                   t₁ = 240/40

                                   t₁ = 6 hours

From equation (4)

                                   t₂ = t₁ + 1

                                   t₂ = 6 + 1  

                                   t₂ = 7 hours

The total time for the trip is t₁ + t₂ = 6 + 7

                                       = 13 hours    

7 0
3 years ago
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