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lakkis [162]
3 years ago
11

PLEASE HELP

Mathematics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

-200 | -500 | -500-(-200) | -300

-200 | -0      | 0 -(-200)     |  200

Step-by-step explanation:

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machine a pops 12.75 oz of popcorn in 3 minutes machine b pops 10 oz of popcorn in 4 minutes which machine pops more popcorn in
Tpy6a [65]

Answer:

  A

Step-by-step explanation:

Machine A pops more popcorn (12.75 vs 10 oz) in less time (3 min vs 4 min), so pops popcorn the fastest.

Machine A pops more popcorn in one minute, on average.

_____

<em>Additional comment</em>

As a practical matter, neither machine may have popped <em>any</em> popcorn in one minute. Generally, one must wait for the cycle to complete. The average overall rate will depend on how quickly each machine can be recycled to produce another batch.

8 0
2 years ago
Choose a method you prefer to solve for a system of linear equations.<br> 2x + 4y = -4<br> 2x-y=6
Artyom0805 [142]

Answer:

Elimination

x = 2

y = -2

Step-by-step explanation:

Elimination

2x + 4y = -4

2x - y = 6

Subtract the second equation from the first

5y = -10

Divide both sides by 5

y = -2

---------------------

Substitute for y = -2 in the second equation

2x - -2 = 6

2x + 2 = 6

subtract 2 from both sides

2x = 4

Divide both sides by 2

x = 2

7 0
2 years ago
Simplify -2(3x-5)+5x<br>​
Sauron [17]
-1x+10 is the answer
8 0
3 years ago
Forty tickets are sold for a raffle with two prizes. You buy two tickets. What is the probability that you will win both prizes
tekilochka [14]
When you first pick a ticket, there are 2 winning tickets and 40 total tickets.  This means that there is a 2/40 chance of your ticket being a winning one.  This fraction can be reduced to 1/20.

After this, there will be 1 winning ticket left and 39 total tickets.  There is a 1/39 chance of the next ticket being a winning one.  We multiply these two fractions together to get our answer.  1/20 * 1/39 = 1/780, so there is a 1/780 chance of having 2 winning tickets.
5 0
3 years ago
I need help with this problem
cupoosta [38]
\bf \begin{cases}&#10;(n^4)^p=n^{12}\to &n^{4\cdot p}=n^{12}\to 4p=12&#10;\\&#10;&\qquad \uparrow \\&#10;&\textit{same bases, thus}\\&#10;&\qquad \downarrow &#10;\\&#10;n^3\cdot n^q=n^6\to &n^{3+q}=n^6\to 3+q=6&#10;\end{cases}&#10;\\\\\\&#10;thus\implies &#10;\begin{cases}&#10;4p=12\implies p=\frac{12}{4}&#10;\\\\&#10;3+q=6\implies q=6-3&#10;\end{cases}&#10;\\\\&#10;&#10;\\\\&#10;then\implies p\cdot q=\boxed{?}
7 0
3 years ago
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