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2 years ago

Find the equation of perpendicular bisector of the lines with the given word (1,2) and (5,4)

Mathematics

1 answer:

Mandarinka [93]2 years ago

7 0

Answer:

y = -2x + 4

Step-by-step explanation:

Slope: (4-2)/5-1) = 2/4 = 1/2

Slope of the perpendicular line: -2

y-intercept: 2 - (-2)(1) = 4

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Nostrana [21]

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2 years ago

What is -2x + 3y = 15 in slope intercept form

garik1379 [7]

slope intercept form

y=mx+b

-2x+3y=15

add 2x to each side

3y =2x+15

divide by 3

y = 2/3 x+5

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2 years ago

-12x - 12y = 4 3x + 3y = 0

Svetradugi [14.3K]

Answer:

no Solution

Step-by-step explanation:

-12x-12y=4\\ 3x+3y=0

12x-12y=4

add 12y to both sides

12x-12y+12y=4+12y

divid both sides by -12

\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}

simplfy

x=-\frac{1+3y}{3}

\mathrm{Substitute\:}x=-\frac{1+3y}{3}

\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}

\begin{bmatrix}-1=0\end{bmatrix}

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2 years ago

WXY is a right triangle. A. True. B. False.

lora16 [44]

Answer:

B. False

Step-by-step explanation:

According to pythagorean theorem, for this to be a right triangle, the sum of square of the length of the two legs must equal square of the length of the hypotenuse (longest side).

So $(\sqrt{34} )^{2}$ should equal $(\sqrt{18} )^{2}+(\sqrt{18} )^{2}$

We also know that $(\sqrt{a} )^{2}=(\sqrt{a})(\sqrt{a})=a$

Hence, $(\sqrt{18} )^{2}+(\sqrt{18} )^{2}=18+18=36$ , and

$(\sqrt{34} )^{2}=34$

They ARE NOT EQUAL, so the triangle is NOT a right triangle.

5 0

2 years ago

Read 2 more answers

I dont get what b) means/asking. someone help pls

GenaCL600 [577]

The question is asking.. Of the total income that Madeleine gets, what percent of it goes to Madeleines expenses.
The way you solve this is divide the total expenses by the total income and multiply by 100.

1840/2020= .9109 .9109*100= 91.09%

8 0

2 years ago

Find the equation of perpendicular bisector of the lines with the given word (1,2) and (5,4) ​

Find the equation of perpendicular bisector of the lines with the given word (1,2) and (5,4)