Answer:
The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
![rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)](https://tex.z-dn.net/?f=rank%28A%29%3Drank%5Cleft%20%28%20%5Cleft%20%5B%20A%7CB%20%5Cright%20%5D%20%5Cright%20%29%5C%3Aand%5C%3An%3Drank%28A%29)
Then satisfying this theorem the system is consistent and has one single solution.
Explanation:
1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
Then the system is consistent and has a unique solution.
<em>E.g.</em>
2) Writing it as Linear system
3) The Rank (A) is 3 found through Gauss elimination
4) The rank of (A|B) is also equal to 3, found through Gauss elimination:
So this linear system is consistent and has a unique solution.
Answer:
it lets you get more work done
Explanation:
when you have a positive work attitude you want to do more stuff, and when it's bad you won't want to do anything
Answer:
vxxgxfufjdfhgffghgfghgffh
Answer:
Three ways to increase the value of variable are given below. To eleborate the answer, I am taking a variable x that need to be increase.
- x=x+1
- x++
- x+=1
Explanation:
There are three ways to increase the value of variable.
1. x= x+1
In this case, each time value of x (variable) is incremented and stored in that variable. This equation increase the value of x by 1 each time. For Example
if x=1
then in first iteration
x= x+1 = 2;
If we want to increase the value of x by more than 1, we can add that value with x, as x+2, x+3 and so on.
2. x++
This will increment the value of x by 1. If we use this equation multiple time in program, each time it will increase 1 in value of x.
3. x+=1
This also works same as equation 1. It will increment 1 in this form and can be changed with 2, 3 and so on.
