x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)
Now, factoring the term:
The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation, the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,
So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
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Be more specific. The decimal can be anywhere give more detail
35
since m and n are the midpoints of ab and ac resistively
then ,bc=2mn=16
since m and l are the midpoints of ba and bc respectively
then, ac =2mn =10
then,nc =1/2 × 10 =5
similary, mb=6
then ,perimeter=nc+mb+mn+bc=5+6+8+16=35
Answer:
A=1, B=3, C=15
Step-by-step explanation:
I think that
1(3x+3)=15
3x+3=15
3x=12
x=4
Gross pay = 500
deductions :
medicare tax : 0.0145(500) = 7.25
S.S tax : 0.062(500) = 31.00
sales tax : 0.02(500) = 10.00
income tax : 0.2(500) = 100
insurance = 20
total deductions : 7.25 + 31 + 10 + 100 + 20 = 168.25
gross pay - deductions = net pay
500 - 168.25 = net pay
331.75 = net pay <===