Answer:
we know that,
y-y1=m(x-x1)
or, y-1=-3(x-5)
or, y-1=15-3x
or 3x+y-16=0 is the required equation
Since there are no choices, the answers to the missing word in the blank is open. I think it is a type of statistic. With that being said, it would be best to introduce the type of statistics. Statistics could either be numerical or categorical. Numerical data pertains to quantitative data; categorical data pertains to classification of data. Both can be represented by numbers, but categorical data does not have have any value. It is only used for classifying categories. <em>Since this data has a significant value, this is a numerical data.</em>
You can see that there is a proportional relationship between X and Y because every 6 of X decreases 3 in Y. In that way you can say is a linear relationship and you can construct a linear equation: Now, to calculate the equation you use: (Y - y1) = y2 - y1 (X - x1) x2 - x1 Let's peek two pairs (1,-4) and (7,-7) (Y - (-4)) = (-7 - (-4)) (X - 1) (7 - 1) <span>Y + 4 = -3 (X - 1)</span> 6 If you want to express the equation as aX + bY + C = 0 Y + 1/2 X + 7/2 = 0 If you want to express the equation as Y= ax + b <span>Y = -1/2X - 7/2</span>
Answer:
30
Step-by-step explanation:
If you plug in 5 for x and 3 for y then the equation would be 3(5)+5(3) or 15+15.
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