Work out the area of a rectangle with base, b = 20mm and perimeter, P = 60mm.

Please explain how you got your answer!!! The dot plots below show the ages of students belonging to two groups of salsa classes

Rudik [331]

Answer:

Group b most likely has a lower mean age of salsa students

Step-by-step explanation:

Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.

Here we are given with two groups that are Group A and Group B

both having total number of students = 20

Here the mean age of the data is addition of the all ages of different students divided by total number of students.

For group a

total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29

= 15 + 40 + 102 + 96 + 87

=340

The mean age of salsa students= 340 ÷ 20 = 17

For group b

total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21

= 42 + 30 + 56 + 80 + 42

=250

The mean age of salsa students= 250 ÷ 20 = 12.5

So the group b most likely has a lower mean age of salsa students

Learn more about Arithmetic Mean here - brainly.com/question/24688366

#SPJ10

7 0

1 year ago

Type the equation for the graphbelow.Pi/3 2piy = [?] sin([ ]x)

Pie

To find the equation of the graph, what we do is to recognize some characteristics of a sine function:

- Amplitude: The amplitude of the sine function is the distance from the middle value or line running through the graph up to the highest point. In this case, the amplitude is 1.

- Period: The period of a sine function is defined as the length of one complete sine wave or one complete cycle of the curve. It can be found using the equation: P=2pi/B.

Why are these characteristics important?

Because the sine function has the following general form:

In this problem, we have A=1 and we know that the period equals 2pi/3. So,

Therefore, the equation of the graph is:

8 0

1 year ago

Do Now 60: What are the formulas to find area for a square, triangle, rectangle, parallelogram, trapezoid, circle, ellipse and e

Alexandra [31]

Answer:

Area of a square = Length × Length

Area of a triangle = 1/2 base × height

Area of a rectangle = Length × breadth

Area of a parallelogram = base × height

Area of a trapezoid = 1/2 × sum of parallel sides × height

Area of circle = π × square of the radius

Area of ellipse = π × product of major and minor radii

Area of equilateral triangle = 1/2 base × height

Step-by-step explanation:

The area of a square is calculated by multiplying the length by itself.

The area of a triangle is calculated by multiplying half the base of the triangle by its height

The area of a rectangle is found by multiplying the length of the rectangle by its breadth

The area of a parallelogram is calculated by multiplying the base of the parallelogram by its height

The area of a trapezoid is found by multiplying half the sum of the two parallel sides by its height

The area of a circle is calculated by multiplying pi by the square of the radius of the circle

The area of an ellipse is found by multiplying pi by the product of the major and minor radii of the ellipse

The area of an equilateral triangle is calculated by multiplying half the base of the triangle by its height. The height is calculated using Pythagoras theorem

5 0

3 years ago

Sin(x+pi/4)-sin(x-pi/4)=1 solve the equation

evablogger [386]

Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)

$sin(x+ \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} \\ sin(x- \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} \\ \\ \\sin(x+ \frac{ \pi }{4} )-sin(x- \frac{ \pi }{4} ) =1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -(sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} )=1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\ cos(x)sin\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\$
$2cos(x)sin\frac{ \pi }{4} =1 \\ sin\frac{ \pi }{4} = \frac{ \sqrt{2} }{2} \\ 2cos(x) \frac{ \sqrt{2} }{2} =1 \\ 2 \cdot \frac{ \sqrt{2} }{2}cos(x) =1 \\ \sqrt{2} cos(x)=1 \\$
$cos(x)= \frac{1}{ \sqrt{2} } \\ x=\pm arccos \frac{1}{ \sqrt{2} }+2 \pi k , k \in Z \\ x=\pm \frac{ \pi }{4} +2 \pi k , k \in Z$

6 0

2 years ago

On Fridays, Harry's school serves a choice of hamburgers or pizza for lunch. 60% of the sixth grade class ate pizza this Friday.

Liono4ka [1.6K]

Let s = # of students in the sixth grade. 60% of these, or 0.60s, ate pizza: thus, 0.60s = 36. Solving for s, s = 36/0.60 = 60.

There are 60 students in the sixth grade.

8 0

3 years ago

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