Question

The length of a rectangle is 3 feet more than twice the width. Find its area if its perimeter is 7 1/3?

Answer 1

Answer:

3+2w=l

2(l+w)=7 1/3

2(3+2w+w)= 7 1/3

6+6w= 7 1/3

-6 both sides

6w=1 1/3

/6 both sides

w=2/9

2/9*2=4/9+3=3 4/9

4/9*3 4/9= 1 43/81

1 43/81