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4 years ago

Write the first five terms of a numerical pattern that begins with 5 and then adds 6

1 answer:

7 0

This pattern forms an arithmetic sequence with the first term $a_1=5$ . The difference between two consecutive terms of this sequence is 6. The rule to calculate the other term of the sequence is is to add 6 to the previous term. This can be archived as shown in the calculations below,

$a_2=a_0+6=5+6=11\\\\a_3=a_2+6=11+6=17\\\\a_4=a_3+6=17+6=23\\\\a_5=a_4+6=23+6=29$

The first terms of this sequence are 5, 11, 17, 23,29.

You might be interested in

WILL GIVE BRAINLIEST!! PLSSSSSS HELP!!!!

forsale [732]

Answer:

1872 cm cubed

Step-by-step explanation:

Volume=Length*Height*Width

We know that the height of the prism is 13 cm.

We also know that the lateral area of the prism is 634 cm squared.

624/4=156

The area of each lateral face is 156 centimeters squared.

The prism's base is a quadrilateral that is regular. This means that the base has equal sides (equilateral) and equal angles (equiangular ).

13x=156

x=12

The base has a side length of 12 cm.

12*13*12=1872

7 0

3 years ago

When a number is decreased by 40 %40% of itself, the result is 6060. what is the number?

WITCHER [35]

X - 0.40x = 60
0.60x = 60
x = 60 / 0.60
x = 100 <== ur number

8 0

3 years ago

The ceiling of Katie’s living room is a square that is 20 ft long on each side. To decorate for a party, she plans to hang crepe

tatyana61 [14]

The room is a square, meaning all four sides are 20ft long.

Because we know all the side lengths, we can find the perimeter of the square by adding the side lengths together.

(20 + 20 + 20 + 20) = 80

Now that we know the perimeter, we have to match this number to the feet of crepe paper.

We can find this by dividing the total length needed by the length a single roll provides.

80 / 8 = 10

Therefore, we know that Katie will have to buy a minimum of 10 rolls if she wants to cover the entire perimeter of the room.

Hope this helps! :)

8 0

3 years ago

If a geometric sequence has a2 = 495 and a6 = 311, approximate the value of the common ratio ???? to four decimal

shtirl [24]

Answer:

$r = 0.8903$

Step-by-step explanation:

given,

a₂ = 495

a₆ = 311

geometric sequence formula

$a_n = ar^{n-1}$

$a_2 = ar^{2-1}$

$a_2 = ar$ ...................(1)

$a_6 = ar^{6-1}$

$a_6 = ar^5$ ................(2)

dividing equation (2) by (1)

$\dfrac{a_6}{a_2} = \dfrac{ar^5}{ar}$

$\dfrac{311}{495} = r^4$

$r^4 = 0.628$

$r = 0.8903$

hence, the common ratio of the geometric sequence is $r = 0.8903$

7 0

3 years ago

Data collected over time on the utilization of a computer core (as a proportion of the total capacity) were found to possess a r

Marianna [84]

Answer:

The probability that the proportion of the core being used at any particular time will be less than 0.10 is 0.08146

Step-by-step explanation:

$\mu =\frac{\alpha }{\alpha +\beta } = \frac{1}{1 + \frac{\beta}{\alpha} }$ 1/3 0.33 = 33.33 %

The Probability of that the proportion of the core being used at any particular time will be less than 0.10 is given by

PDF = $\frac{x^{\alpha -1} (1-x)^{\beta -1} }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$

where x = 0.1

α = 2 and β = 4

PDF = $\frac{0.0729 }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 1.458

CDF = $\frac{\int\limits^{0.1}_0 {t^{\alpha -1} (1-t)^{\beta -1}} \, du }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 0.08146

The probability that the proportion of the core being used at any particular time will be less than 0.10 = 0.08146.

3 0

4 years ago