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Lemur [1.5K]
3 years ago
11

Large ears Survival Advantage

Biology
2 answers:
Anna71 [15]3 years ago
8 0

Answer:

what?

Explanation:

Free_Kalibri [48]3 years ago
6 0

Answer:

They can be used to cool off

Explanation:

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Describe two characteristics shared by ecosystems that have high biodiversity (DESCRIBE)
svet-max [94.6K]

they deleted my link but if u google this theres a pdf that should help

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3 years ago
Cellular (aerobic) respiration taking place on the presence of and with the use of which of the following
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Aerobic respiration is the release of energy from glucose or another organic substrate in the presence of Oxygen. Strictly speaking aerobic means in air, but it is the Oxygen in the air which is necessary for aerobic respiration. ... ATP can provide energy for other processes such as muscle contractions.

5 0
3 years ago
Monohybrid Mice, i need help
Katyanochek1 [597]

Answer/Explanation:

  • <em>See attached images showing the crosses on a Punnett square as well as the genotype and phenotypes of each cross.</em>

I. Cross between a female Gg with a male gg (GG X gg):

1. Probability of getting gray offspring (Gg) = 2/4 (¼+ ¼) = ½  

2. Probability of getting albino offspring (gg) = 2/4 (¼+ ¼) = ½

3. There are 2 possible genotypes among the offspring, which are Gg and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = ½ + 0 = ½  

7. The color of the female that was crossed (i.e. Gg), is gray color. The allele for gray coat color (G) is dominant over the allele for albino coat color (g).

8. The color of the male (gg) that was crossed is albino. The recessive allele (g) for albino coat color, in its homozygous state would express itself in the absence of the dominant G allele for gray color.

II. Cross between homozygous gray female with a heterozygous male (GG X Gg):

1. Probability of getting gray offspring (GG or Gg) = 4/4 (i.e. ¼+ ¼ + ¼ + ¼ ) = 1  

2. Probability of getting albino offspring (gg) = 0  

3. There are only 2 possible genotypes among the offspring, which are GG and Gg.

4. There is only 1 possible phenotype among the offspring, which is gray coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 (i.e. ¼+ ¼ ) = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = 0 + ½  = ½  

7. The genotype of the female that was crossed is GG, given that the female is homozygous gray.

8. The male crossed is a heterozygous male (Gg), the male is gray.

III. Cross between a gray female, whose father was albino, with a heterozygous male (Gg X Gg):

We can make a good guess of the genotype of the female, given that gray color is dominant over albino, and the father was albino (gg). The father can only contribute sperm having only (g) allele, while the mother must contribute only a (G) allele to give a gray offspring. The gray female is definitely heterogyzous female i.e Gg

1. Probability of getting gray offspring (Gg or GG) =  ¾ (½ + ¼)  

2. Probability of getting albino offspring (gg) = ¼

3. There are 3 possible genotypes among the offspring, which are GG, Gg, and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 = ½  

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = ¼ + ¼ = ½  

7. The genotype of the female is Gg. We know this because we were given that it is gray in color, and gray is dominant over albino. Also, given that the father was albino (gg), a (g) allele can only be contributed by the father to combine with the dominant (G) allele to give us a female that has heterozygous gray coat color (Gg).

8. The genotype of the male is Gg. We know this because we were given that it was a heterozygous male. If an organism is heterozygous, it has different alleles controlling that trait.

IV. Cross between an albino female, whose father was gray, with a gray male, whose mother was albino (gg X Gg):

The albino female’s genotype is gg, because the g allele is recessive. The gray male’s genotype, whose mother was albino (gg) is definitely Gg, because gray is dominant, and to get a gray offspring, a G allele from the mother of the male must combine with the g allele that the albino father can only contribute i.e. Gg or GG from mother X gg from father = Gg (the gray male offspring).

1. Probability of getting gray offspring =  ¼ + ¼ = ½  

2. Probability of getting albino offspring (gg) = ¼ + ¼ = ½  

3. There are 2 possible genotypes among the offspring, which are Gg, and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = ¼ + ¼  = ½  

6. Probability of getting homozygous offspring (i.e. gg or GG) = ½ + 0 = ½  

7. The genotype of the gray father of the albino female (gg) is Gg. Of the two possible genotypes of the gray father (i.e. GG or Gg), Gg is the most likely genotype to contribute the recessive g allele that would pair up with another g allele from the mother to give an albino female (gg), i.e. Gg (father) X Gg (Mother) or Gg (Father) X gg (Mother) = gg (albino female)

5 0
3 years ago
Distinguish between the fossils of ice age mammals found in the La Brea Tar Pits and the organisms that make up the
Neko [114]

Answer:

Explanation:

The tar located in the La Brea tar pits is today a fossil fuel that began its formation many hundreds of millions of years ago from the bodies of marine organisms. During the last ice age that ended a few tens of thousands of years ago, some animals got trapped in the tar and left their bones behind. They are not something that created it but only got trapped in preexisting tar.

4 0
3 years ago
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7 0
3 years ago
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