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kirill [66]
3 years ago
7

Marley is a waitress. On Thursday, she earned $4.60 per hour plus $50.25 in tips. How many hours did she work that day if she ea

rned $87.05
Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Subtract tips from total:

87.05 - 50.25 = 36.80

Divide the remainder by 4.60:

36.80 / 4.60 = 8

She worked 8 hours.

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HELPPP
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Answer:

HL (Hypotenuse Leg)

Step-by-step explanation:

You have BC=CD (Because of reflexive property), AC=DC, and measure of BAC is equal to the measure of BDC, which is 90 degrees. Since these triangles are right and they have a hypotenuse and a leg congruent, you can say that they are congruent because of HL.

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3. Susan earns money by babysitting for relatives and neighbors. She charges $10 per
pshichka [43]

Answer:

e= 10h+5

Step-by-step explanation:

h is no of hours

e is earnings

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Graph the function: y=x-5​
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Answer:

Step-by-step explanation:

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3 years ago
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If you roll a fair die two times, what is the probability of rolling an odd number then rolling a 6 on the same die?
pshichka [43]

Answer:

Step-by-step explanation:

Explanation: The probability of rolling a 2 on a 6-sided dice is 16 . The probability of rolling two 2s on two 6-sided die is, by the multiplication principle, 16×16=136 .

7 0
3 years ago
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An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre
melamori03 [73]

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \mu = <u><em>mean power consumption for microwave ovens.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, H_A : \mu > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                                T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean power consumption for ovens = 257.3 W

            σ = population standard deviation = 15 W

            n = sample of microwave ovens = 20

So, <em><u>the test statistics</u></em>  =  \frac{257.3-250}{\frac{15}{\sqrt{20} } }

                                      =  2.176

The value of z test statistics is 2.176.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

7 0
3 years ago
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