Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
G(2) = -4(2) = -8
f(g(2)) = (-8)^2 = 64
answer
64
Your first answer is correct but I’m not sure if your second is. But I’m leaning towards it is not correct.
Hope this helps!
(Don’t forget to mark branliest if it is correct :) )
Answer:
5
Step-by-step explanation:
Y=30x+50
y is the total amount saved
x is the amount of months she deposited 30 dollars
30 is the amount she’s depositing
50 is the initial amount or the constant