${x}^{2} + 4x - 12 = 0 \\ {x}^{2} + 4x + 4 - 4 - 12 = 0\\ {(x + 2)}^{2} - 16 = 0 \\ x = - + \sqrt{16} - 2 \\ x = + \: or - 4 - 2 \\ x = - 6 \: \: x = 2$
- subtract the 12 from both sides so that it becomes the last constant term in the quadratic equation which should now equal 0.
- take the 4x
- half the coefficient of 4 (2)
- square it (4)
- add it to the equation (+4)
- subtract it from the equation (-4)
- factorise the square (x+2)^2 expands to (x^2 + 4x + 2) as {a+b}^2={a^2 + ab + ba + b^2}
- now the equation is in turning point form.
- to find x, add 16 and square root 16 and (x+2)
- subtract 2 from positive or negative 4 (as -4^2 and 4^2 both equal 16).
- This should give you two values for x, -6 and 2.

I really hope that this helped :)

7 0

2 years ago

Genesis throws a ball up in the air. The graph below shows the height of the ball hh in meters after tt seconds. Find the interv

Juli2301 [7.4K]

We conclude that the interval in which the function decreases is (1.5, 3]

<h3>In which interval is the ball's height decreasing?</h3>

The ball is decreasing when the graph, reading from left to right, is going downwards.

Particularly, in this parabola that opens downwards, the graph will decrease after the vertex.

And we can see that the vertex is at x = 1.5

And we also see that the graph of the function ends at x = 3.

Then we conclude that the interval in which the function decreases is (1.5, 3]

If you want to learn more about parabolas:

brainly.com/question/4061870

#SPJ1

5 0

1 year ago

-11 2/3 x (-4 1/5) pls help me​

-11 2/3 x (-4 1/5) pls help me