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elixir [45]
3 years ago
13

Answerr this. Will also give branliest. helpp

Mathematics
2 answers:
leva [86]3 years ago
6 0

∠1 and ∠9 = Corresponding angles

∠2 and ∠3 = Same side interior angles

∠8 and ∠12 = Other

∠6 and ∠12 = Alternate interior angles

∠1 and ∠2 = Lineae pair

∠15 and ∠11 = Alternate interior angles

∠8 and ∠9 = Same side interior angles

∠2 and ∠4 = Corresponding angles

il63 [147K]3 years ago
4 0

Answer:

Angles 1 and 9 are corresponding angles

2 and 3 same side interior angles

8 and 12 are OTHER

6 and 12 are alternate interior

1 and 2 are linear pairs

15 and 11 are alternate interior

8 and 9 are same side interior

2 and 4 are corresponding

Step-by-step explanation:

Use the graph!

Brainliest??Hope it helped!

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Which of the following rational functions is graphed below?
podryga [215]

Answer:

c

Step-by-step explanation:

Oblique Asymptotes

R(x) will have oblique asymptote if it can be represented in the form

1 / (Q)x

4 0
2 years ago
Hello, could you help me with my math exercise? thank you in advance
Natali [406]

Answer:

100(x - 1)

Explanation:

Let's begin writing down everything

(X×(-11)+5)×(-9)+X-55

Now we can multiply

-9(-11X+5)+X-55

99X-45+X-55

And so we get

100X-100

Factorize 100

100(x-1)

4 0
3 years ago
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The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max
siniylev [52]

Answer:

A) The maximum error in the calculated surface area: 25cm^2

Relative error: 0.013

B) The maximum error in the calculated volume: 162cm^2

Relative error: 0.019

Step-by-step explanation:

A) The formula for the surface area is:

A=4\pi r^2

The measured value is the circumference which is equal to:

C=2\pi r

then the radius is:

r=\frac{C}{2\pi}

Substituting in the formula of the surface:

A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}

Using the formula to calculate the error:

dy=f'(x)dx

Where x is the variable measured and y is a function of x(y=f(x)).

dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC

We have C=80cm and dC=0.5cm

dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2

The relative error is the maximum error divide by the total area. The total area is: A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2

\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013

B) The formula for the volume is:

V=\frac{4}{3} \pi r^3

Using r=\frac{C}{2\pi}

V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}

The maximum error is:

dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2

The calculated volume is:

V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743

The relative error is:

\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019

3 0
3 years ago
The mass of an adult North Pacific right whale is about 70,000 kg, or 7 x 104
olasank [31]

Answer:

Answer B: 1*10^2 times

Step-by-step explanation:

To find how many times more massive is the whale relative o the polar bear, we just need to find the quotient of one over the other:

\frac{7*10^4}{7*10^2} = \frac{7*10^2*10^2}{7*10^2}=1*10^2 times

Therefore our answer agrees with the one shown as answer B.

6 0
3 years ago
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dexar [7]
$17 for an adult ticket
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