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Romashka-Z-Leto [24]
3 years ago
13

PLEASE HELP ASAP I NEED HELP PLEASE

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

It isn't a proportional relationship

Step-by-step explanation:

It's not a proportional relationship because you would have to divide both numbers on the chart by a number they both have in common and when you divide them and it doesn't equal 0 then it is not a proportional relationship.

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Write the standard form of the equation of the circle with radius 4 and center (−7,−6).
olasank [31]

The equation of a circle is written as (x-h)^2 +(y-k)^2 = r^2

h is the x value of the center and k is the y value of the center and r is the radius.

Replace h, k and r with the given information:

(x- -7)^2 + (y - -6)^2 = 4^2

Simplify:

(x+7)^2 + (y+6)^2 = 16

4 0
3 years ago
You have 9 math coins and each coin is worth -25 points. How many points is that all together?
lesya [120]
The answer is -225.
9 times -25 is -225.
9*-25=-225
6 0
3 years ago
Read 2 more answers
7 - 4 ( d - 3 ) = 23
astra-53 [7]

7 - 4 ( d - 3) = 23

7 - 4d + 12 = 23

Subtract 12 from both sides,

7 - 4d = 11

Subtract 7 to both sides

- 4d = 4

Divide -4 to both sides

d = -1

8 0
3 years ago
Read 2 more answers
Pam started watching a movie at 2:53 P.M. The movie was 1 hour and 52 minutes long. After the movie, Pam rode her bike for 46 mi
Karo-lina-s [1.5K]

The time Pam got home is 5:25 pm.

<h3>How to calculate time </h3>

Remember that 60 minutes is equivalent to 1 hour. When adding minutes together, when the minutes exceeds 60, convert to an hour.

<h3>How to determine the time Pam got home</h3>

In order to determine the time she got home, add the time she used to watch the movie , to the time she used to ride her bike home to the time the movie started.

2:53 + 1:52 + 46 = 5:25 pm

To learn more about addition, please check: brainly.com/question/19628082

7 0
2 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

t = 2.69

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
2 years ago
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