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DiKsa [7]
3 years ago
8

Ali surveyed his classmates to see who liked tennis. In all, 32 males liked tennis, and 6 males did not like tennis; 13 females

liked tennis, and 4 females did not like tennis. How many females did Ali survey
Mathematics
1 answer:
ANEK [815]3 years ago
5 0

Answer:

Ali surveyed 17 females.

Step-by-step explanation:

From Ali's survey:

13 females liked tennis, while 4 did not.

This means that Ali's surveyed 13 + 4 = 17 females.

How many females did Ali survey?

Ali surveyed 17 females.

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Convert 4.824 meters per second to kilometers per hour.
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Step-by-step explanation:

17.3664

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4 years ago
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You are dealt two cards successively without replacement from a standard deck of 52 playing cards. Find the probability that the
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Answer:

\frac{4}{52} \times \frac{4}{51}  = \frac{16}{2652} = 0.00603 = 0.603\%

Step-by-step explanation:

There are 52 cards in a standard deck, and there are 4 suits for each card. Therefore there are 4 twos and 4 tens.

At first we have 52 cards to choose from, and we need to get 1 of the 4 twos, therefore the probability is just

\frac{4}{52}

After we've chosen a two, we need to choose one of the 4 tens. But remember that we're now choosing out of a deck of just 51 cards, since one card was removed. Therefore the probability is

\frac{4}{51}

Now to get the total probability we need to multiply the two probabilities together

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5 0
3 years ago
In a survey of 100 out-patients who reported at a hospital on a day, it was found that 70 complained of fever, 50 had stomach tr
cluponka [151]

Answer:

3 patients had all the three complaints

Step-by-step explanation:

Let U be the set of patients who reported at the hospital on that day

Let F be the set of patients who complained of fever

Let S be the set of patients who had stomach troubles

Let I be the set of injured patients

Then the given data can be written as:

  • n(U) = n(F∪S∪I) = 100
  • n(F) = 70
  • n(S) = 50
  • n(I) = 30
  • n(F∩S) + n(S∩I) + n(I∩F) - 3×n(F∩S∩I) = 44

n(F∩S∩I) = ?

Using the formula for the cardinal number of union of three sets:

n(F∪S∪I) = n(F) + n(S) + n(I) - n(F∩S) - n(S∩I) - n(I∩F) + n(F∩S∩I)

100 = 70 + 50 + 30 - (44 + 3×n(F∩S∩I)) + n(F∩S∩I)

100 = 150 - 44 - 2×n(F∩S∩I)

2×n(F∩S∩I) = 106 - 100 = 6

<u>n(F∩S∩I) = 3</u>

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Answer:

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Yes  you can form a triangle with those angles

Step-by-step explanation:

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