Answer:
a. 0.6899
b. 0.1642
Step-by-step explanation:
a. Given the probability of success is 0.94 for an expert and that the number of pairs, n=6:
-Each attempt is independent and therefore the probability of the events is calculated as:
Hence, the probability of correctly identifying the 6 matches is 0.6899
b.Given the probability of success is 0.74 for a novice and that the number of pairs, n=6:
-Each attempt is independent and therefore the probability of the events is calculated as:
#Hence, the probability of correctly identifying the 6 matches is 0.1642
*I have used the sample size of 6(due to conflicting info/question size).
Answer:
x^3 +x^2 +x+1
Step-by-step explanation:
Your welcome!!!!!!!!!!!
Answer:
The answer to your question is:
x = 1
y = 1
z = 0
Step-by-step explanation:
-2x + 2y + 3z = 0 (1)
-2x - y + z = -3 (2)
2x + 3y + 3z = 5 (3)
Solve (1) and (2)
Multiply 2 by 2
-2x + 2y + 3z = 0
-4x -2y + 2z = -6
-6x + 5 z = -6 (4)
Solve (2) and (3)
Multiply 2 by 3
-6x - 3y + 3z = -9
2x + 3y + 3z = 5
-4x + 6z = -4 (5)
Solve (4) and (5)
Multiply (4) by 2 and (5) by -3
-12x + 10 z = -12
12x - 18z = 12
-6z = 0
z = 0
Then
-4x + 6(0) = -4
-4x = -4
x = -4/-4
x = 1
Finally
-2(1) - y + (0) = -3
-2 - y = -3
-y = -3 + 2
y = 1
Answer:
25.50=3.75h+0.50d
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height
Suppose they have same mass and radius
time Period is given by
,where h=height of release
a=acceleration
Where I=moment of inertia
a for hoop
a for Uniform solid cylinder
a for spherical shell
a for Uniform Solid
time taken will be inversely proportional to the square root of acceleration
thus first one to reach is Solid Sphere
second is Uniform solid cylinder
third is Spherical Shell
Fourth is hoop