Question

What is the slope of the line that contains these points? xxx -4−4minus, 4 -3−3minus, 3 -2−2minus, 2 -1−1minus, 1 yyy 222 555 888 111111

Answer 1

Given:

The table of values is

x        y

-4      2

-3      5

-2       8

-1       11

To find:

The slope of the line that contains these points.

Solution:

From the given table consider any two point.

Let the line passes through the points (-4,2) and (-3,5). So, the equation of the line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-2=\dfrac{5-2}{-3-(-4)}(x-(-4))$

$y-2=\dfrac{3}{-3+4}(x+4)$

$y-2=\dfrac{3}{1}(x+4)$

Using distributive property, we get

$y-2=3x+12$

$y=3x+12+2$

$y=3x+14$

Therefore, the required equation of line is $y=3x+14$.