All categories

3 years ago

Help help help help what is the answer −5(4x−3)−x+5=190!!!

Mathematics

1 answer:

artcher [175]3 years ago

8 0

X=8.5
190-5=185
185/-5=-37
-37-3=-34
34/4=8.5

You might be interested in

I don’t know how to solve for Q.

Naya [18.7K]

Answer:

∠Q = 75°

Step-by-step explanation:

Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.

Next, you use the fact that the sum of angles is 180° to write an equation.

∠R +∠P +∠Q = 180°

(2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values

5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms

5x = 150 . . . . . . . . subtract 30

x = 30 . . . . . . . divide by 5

Then angle Q is ...

∠Q = (2x +15)° = (2×30 +15)°

∠Q = 75°

8 0

2 years ago

A train is traveling at a constant speed. The table shows the distance the train travels at different times during the trip. How

SpyIntel [72]

The train is traveling at 165 mph

495/3=165
825/5=165
1155/7=165
1485/9=165

8 0

3 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

What integers are plotted on the number line below?

qaws [65]

Answer:

The answer is c. hope this helps

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which expression is equivalent to (4^−3)^−6?

Alex777 [14]

Answer

4^ 18

i hope this is what your looking for

4 0

2 years ago