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MaRussiya [10]
2 years ago
9

Factorise 15x-5 factorise x^2-5x+6

Mathematics
1 answer:
kotegsom [21]2 years ago
5 0
5(3x-1) (x-3)(x-2) I don't know if you want working out or an explanation? Or if it's too late, sorry.
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What is the author's primary purpose in writing this
Sauron [17]

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he worked hard and hus purpose is to teach people how to learn I guess he wants the reader to know how hard time they spended his secondary purpose is to teach the value of time to people.....

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¿Cuántos pesos valen 125 litros de leche a 1/5 de pesos en litro?
Lana71 [14]

1 / 5 = 0.2 pesos.

125 * 0.2 = 25 pesos el litro

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3 years ago
In a video store, a DVD that sells for $15 is marked "10% off." What is the discount? What is the sale price of the DVD?
Margarita [4]

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3 years ago
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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

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3 years ago
Help (fraction) problem :(
Nastasia [14]

Answer:

it's 8 4/6 because you have to make the denominator all 6 so you would have to mutiply the bottom and do the same for the top keep the whole number the same and then add it all up you'll get 8 4/6

4 0
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