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fgiga [73]
2 years ago
6

Multiply and collect like terms: (3q−8)(q−1).

Mathematics
1 answer:
yanalaym [24]2 years ago
7 0

Combine like terms

3q^2 − 11q + 8

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What is <br> not a characteristic of a point
azamat

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Find the perimeter use pi
balandron [24]
Since d x pi = circumference
I use 3.14 as pie

I did 9 x pi = 28.26 I DID NOT divide this by two because there are three half circles and 28.26 counts as two of them

Since there is another half circle I divide 28.26 by 2

28.26 + 14.13 = 42.39

Now plus the bottom length

42.39 + 9 = 51.39


Brainliest answer please?
8 0
3 years ago
The diagram shows the ratio of trees Maeve plants to the trees she harvests.<br> Thank u
Sveta_85 [38]

Answer:

Wednesday is 45 to 18.

Thursday is 55 to 22

Step-by-step explanation:

Wednesday: The original ratio was 5 to 2 And the info tells us that the new ratio is ? to 18. To find the first part we have to find how we got from 2 to 18. 2 * 9 = 18. So to find out the first part you do 5 * 9 = 45. We multiply 5 because Thats the original 1st part. We multiply 9 because that's how we got to 18 in the 2nd part. So the answer is 45 for Wednesday.

Thursday: The original ratio was 5 to 2 And the info tells us that the new ratio is 55 to ?. To find the first part we have to find how we got from 5 to 55. 5 * 11 = 55. So to find out the 2nd part you do 2 * 11 = 55. We multiply 2 because That's the original 2nd part. We multiply 11 because that's how we got to 55 in the 1st part. So the answer is 22 for Thursday.

4 0
3 years ago
HELP ILL GIVE BRAINLIEST
Ksenya-84 [330]

Answer:

A: 40%

B: 75%

C: 90%

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a
inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

a,b, \text{ and } c.

We are given the sum is 36: a+b+c=36.

One of our numbers is a perfect cube. a=n^3 where n is an integer.

The other two numbers are factors of 20. bk=20 and ci=20 where a,c,i, \text{ and } k \text{ are integers}.

n^3+\frac{20}{k}+\frac{20}{i}=36

From here I would just try to find numbers that satisfy the conditions using trial and error.

3^3+\frac{20}{2}+\frac{20}{2}

27+10+10

47

3^3+\frac{20}{4}+\frac{20}{5}

27+5+4

36

So I have found a triple that works:

27,5,4

The numbers in ascending order is:

4,5,27

4 0
3 years ago
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