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Phoenix [80]
4 years ago
7

When we jump on a concrete surface the feet are more seriously hurt than while jumping on a sand

Physics
1 answer:
ohaa [14]4 years ago
4 0
<span>In this situation when using newton's third law, the floor is very rigid and thus when we fall the floor applies the same amount of force on us with which we were falling on it. The rigidness of the concrete floor makes it difficult for it to absorb some of our force. On the other hand sand is not rigid on impact sine it changes its shape while it absorbs a large amount of our falling force and a small fraction of this force is applied on is. That is why we don't get hurt</span>
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Explanation:

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Difference between regular and irregular object.​
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5 0
4 years ago
1. A gas enclosed in a cylinder occupies 0.030 m3. It is compressed under a constant pressure of 3.5 x 10^5 Pa until it's final
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5 0
3 years ago
A galvanometer with a resistance of 40.0 ω deflects full scale at a current of 2.0 ma. what resistance should be used with this
kogti [31]
The resistance needed to be added is R
The Current is 2 ma
The voltage reading is a maximum of 50 volts.
The ma meter has an internal resistance of 40 ohms.

Formula
E = I * R

Givens
E = 50
I = 2 ms
R = R + 40

Solution
E = I * R
I = 2 ma [ 1 amp / 1000 ma] = 0.002 amp
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50/0.002 = R + 40
25000 = R + 40 Subtract 40 from both sides.
R = 25000 - 40
R = 24960     Answer

8 0
4 years ago
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