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snow_tiger [21]
3 years ago
5

Describe Charle’s Law and Boyle’s Law.

Physics
1 answer:
ch4aika [34]3 years ago
8 0

Explanation:

Boyle's law can be stated as the "volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant". It is mathematically expressed as;

    P1 V1  = P2 V2

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

Charles's law states that the volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant.

It is mathematically expressed as;

            \frac{V1}{T1}    = \frac{V2}{T2}  

V and T are volume and temperature respectively

1 and 2 are the initial and final states

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A non <span>foliated </span>rock has interlocking grains with no specific pattern.
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3 years ago
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Predict changes in state according to change in particle motion. Know the vocabulary used to describe changes of state.
ziro4ka [17]

The change in the state of matter causes change in the motion of the particles of the matter. The gaseous state of matter has the greatest speed while the solid state has the least speed.

The change in state of every matter is accompanied by lost or gained of energy.

Example is water.

The solid state of water is ice. The motion of particles of the water is relatively zero because the molecules are held at a fixed position.

The liquid state of water occurs when the temperature of the ice is increased above zero degree Celsius. The speed of the particles of water in liquid state is greater than solid state.

The gaseous state of water occurs when the temperature of the liquid water is increased beyond 100 degree Celsius. The speed of water in gaseous state is greater than liquid state.

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7 0
2 years ago
A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
If we use 1 millimeter to represent 1 light-year, how large in diameter is the Milky Way Galaxy?
storchak [24]

Answer:

d.100 meters

Explanation:

The diameter of the Milky Way Galaxy is approximately 100,000 light years.

Here we are using 1 millimiter (1 mm) to represent 1 light-year (1 ly). So, we can set the following proportion:

1 mm : 1 ly = x : 100,000 ly

and by finding x, we find the diameter of the Milky Way Galaxy in the scale used:

x=\frac{(1mm )(100,000 ly)}{1 ly}=100,000 mm = 100 m

so the correct answer is

d. 100 meters

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3 years ago
Maxwell shoots a rubber band at his friend Jimmy. Which type of energy is converted into kinetic energy?
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A stretched rubber band is storing <em>elastic potential energy. (A)</em>

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