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SSSSS [86.1K]
3 years ago
11

PLS HELP 30 POINTS IF U HELP

Physics
2 answers:
USPshnik [31]3 years ago
8 0

Answer:

its D so yeah.........

Explanation:

tell me if it's wrong

Neko [114]3 years ago
3 0

Answer:

69,420

Explanation:

OOOOOHHHH YYYEEEAAAHHH AKA D

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A 0.210-kg metal rod carrying a current of 11.0 A glides on two horizontal rails 0.490 m apart. If the coefficient of kinetic fr
sergij07 [2.7K]

Answer:

The  magnetic field is  B = 0.0764 \ T

Explanation:

From the question we are told that  

    The mass of the metal is  m  =  0.210 \ kg

     The current is  I  =  11.0 \ A

      The distance between the rail(length of the rod ) is  d  =  0.490 \ m

      The coefficient of kinetic friction is  \mu_k  =  0.200

Generally the magnetic force is mathematically represented as

      F_b  =  B *  I  *  d

Given that the rod is moving at a constant velocity, it

=>    F_b  =  F_k

Where F_k is the kinetic frictional force which is mathematically represented as

       F_k  =  \mu_k  *  m *  g

So

    B *  I  *  d =  \mu_k  * m * g

=>   B =  \frac{\mu_k  * m * g}{I  *  d }

substituting values

=>   B =  \frac{0.200  * 0.210  * 9.8 }{ 11  *  0.490 }

=>   B = 0.0764 \ T

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3 years ago
What are earthquakes usually associated with?
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Earthquakes are normally associated when two tectonic plates move away from each other causing a rift in the plate and you get an earthquake.

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3 years ago
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Autism spectrum disorder is marked by all but which of the following categories of symptoms?
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2 years ago
A 4.0-kg block is pushed up a 36 incline by a force of magnitude P applied parallel to the incline. When P is 31 N, it is obser
denpristay [2]

Answer:

15.1 N

Explanation:

mass of block (m) = 4 kg

angle of inclination = 36 degrees

applied force (P) = 31 N

acceleration due to gravity (g) = 9.8 m/s^{2}

since the block is moving at a constant speed, it means the acceleration is 0 and therefore the summation of all the forces acting on the body is 0

therefore

P - f - mgsinθ = 0

where

  • P = applied force
  • f = frictional force
  • m = mass
  • g = acceleration due to gravity
  • θ = angle of inclination

when P = 31 N and the block is pushed upward

31 - f - (4 x 9.8 x sin 36) = 0

f = 7.96 N

now that we have the value of the frictional force we can find P required to lower the block, our equation becomes p + f - mgsinθ = 0 since the block is to be lowered

P + f - mgsinθ = 0

P = mgsinθ - f

P = (4 x 9.8 x sin 36) - 7.96 = 15.1 N

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