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3 years ago

PLS HELP 30 POINTS IF U HELP

Physics

2 answers:

USPshnik [31]3 years ago

8 0

Answer:

its D so yeah.........

Explanation:

tell me if it's wrong

Neko [114]3 years ago

3 0

Answer:

69,420

Explanation:

OOOOOHHHH YYYEEEAAAHHH AKA D

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A double-slit interference pattern is created by two narrow slits spaced 0.21 mm apart. The distance between the first and the f

olga nikolaevna [1]

Answer:

$\lambda =533.6 nm$

Explanation:

the slits spacing, d = 0.21 mm

distance of screen, D = 61 cm

The condition for minima is given as

$dsin(\theta) = \left ( n+\frac{1}{2} \right )\lambda$

So, first minima, n = 0

$dsin(\theta_1) = \frac{1}{2}\lambda$

fifth minima, n = 4

$dsin(\theta_5) = \frac{9}{2}\lambda$

$d(sin(\theta_5) -sin(\theta_1))= 4\lambda$

For small angle

$d(tan(\theta_5) -tan(\theta_1))= 4\lambda$

From the figure:

$d(\frac{y_5}{D}-\frac{y_1}{D})= 4\lambda$

$\frac{d}{D} (y_5-y_1) = 4\lambda$

$\lambda = \frac{d}{4D} (y_5-y_1)$

$\lambda = \frac{0.021}{4(61)} (6.2 \times 10^{-3})$

$\lambda =533.6 nm$

4 0

3 years ago

Which person will experience what happens to sounds due to the Doppler effect?

horsena [70]

Answer:

Explanation:

as toddler will go away then come closer

6 0

3 years ago

Picture is below! Thank you

Sergio039 [100]

Answer:

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3 years ago

A 12.0N force with a fixed orientation does work on a

kvasek [131]

Answer:

(a) $\theta=62.31^{\circ}$

(b) $\theta=117.68^{\circ}$

Explanation:

It is given that,

Force acting on the particle, F = 12 N

Displacement of the particle, $d=(2.00i -4.00j+3.00k)\ m$

Magnitude of displacement, $d=\sqrt{2^2+4^2+3^2}= 5.38\ m$

(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :

$W=Fd\ cos\theta$

$\theta$ is the angle between force and the displacement

According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.

So,

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{+30\ J}{12\times 5.38}$

$\theta=62.31^{\circ}$

(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{-30\ J}{12\times 5.38}$

$\theta=117.68^{\circ}$

Hence, this is the required solution.

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3 years ago

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Stells [14]

Yes yes yes yes yes yes yes yes

4 0

3 years ago

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