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Physics

2 answers:

USPshnik [31]3 years ago

8 0

Answer:

its D so yeah.........

Explanation:

tell me if it's wrong

Neko [114]3 years ago

3 0

Answer:

69,420

Explanation:

OOOOOHHHH YYYEEEAAAHHH AKA D

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A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.

FinnZ [79.3K]

We have that the maximum height reached by the basketball from its release point is

$S=1.3m$

From the question we are told

A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
What is the maximum height reached by the basketball from its release point?

Generally the Newtons equation for Motion is mathematically given as

$V^2=u^2+2as\\\\Therefore\\\\0=25-19.6*S\\\\S=\frac{25}{19.6}\\\\S=1.276$

$S=1.3m$

Therefore

The maximum height reached by the basketball from its release point is

$S=1.3m$

For more information on this visit

brainly.com/question/23366835

4 0

3 years ago

A meteorite has a speed of 90.0 m/s when 850 km above the Earth. It is falling vertically (ignore air resistance) and strikes a

Schach [20]

Before it hits the sand bed, the meteorite is accelerating uniformly with $g=9.80\dfrac{\rm m}{\mathrm s^2}$ , so that its speed $v$ satisfies

$v^2-{v_0}^2=-2g\Delta y$

where $v_0=90.0\dfrac{\rm m}{\rm s}$ is its initial speed and $\Delta y=(0-850)\,\mathrm{km}=-850\,\mathrm{km}$ is its change in altitude. Notice that we're taking the meteorite's starting position in the atmosphere to be the origin, and the downward direction to be negative. Now,

$v^2-\left(-90.0\dfrac{\rm m}{\rm s}\right)^2=-2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(-850,000\,\mathrm m)\implies\boxed{v=4080\dfrac{\rm m}{\rm s}}$