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4 years ago

What is homeostasis?

2 answers:

3 0

Homeostasis maintains internal balance of the cell.-- Things like shiver if cold sweating if hot to maintain internally

Harrizon [31]4 years ago

3 0

Answer:

Homeostasis is the cells response to its environment.

Explanation:

Homeostasis is the cell response to its environment to maintain its steady state between internal conditions and outer environment. Here cell maintains cell temperature, fluid balance, sugar balance etc through it ( keep it in a pre-decided range known as homeostatic range) Ex:- when their is cold outside we start shivering and get energy to maintain our body temperature.

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A motor does 3,441 joules of work in 13.66 seconds. What is the power of the motor?

il63 [147K]

Answer:

Power = 251.9 Watts

Explanation:

Power = Work Done / Time taken

Power = 3441 / 13.66

Power = 251.9 Joule / Second

Power = 251.9 Watts

5 0

3 years ago

Assume that a friend hands you a 10-newton box to hold for her. If you hold the box without moving it at a height of 10 meters a

malfutka [58]

Answer:

100 Joules

Explanation:

Applying,

W = mgh................... Equation 1

Where W = workdone to hold the box above the ground, mg = weight of the box, h = height of the box.

From the question,

Given: mg = 10 newtons, h = 10 meters.

Substitute these values into equation 1

W = 10×10

W = 100 Joules.

Hence the amount of workdone is 100 Joules

7 0

3 years ago

A current 2a flows in a circuit fir 2 minutes. Calculate the charge generated in a circuit

nirvana33 [79]

Answer:

the charge generated in the circuit is 240 C.

Explanation:

Given;

current flowing in the circuit, I = 2A

time of current flow, t = 2 minutes = 2 x 60s = 120 s

The current flowing through a given circuit is defined as the quantity of charge flowing through the circuit in a given time.

$I = \frac{Q}{t} \\\\Q = I t$

where;

Q is the charge flowing in the circuit

Q = 2 x 120

Q = 240 C

Therefore, the charge generated in the circuit is 240 C.

3 0

4 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change

olga55 [171]

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

7 0

3 years ago

A 149 turn 149 turn circular coil of radius 2.15 cm 2.15 cm is immersed in a uniform magnetic field that is perpendicular to the

adoni [48]

Answer:

Explanation:

number of turns, N = 149

radius, r = 2.15 cm

Area, A = πr² = 3.14 x 2.15 x 2.15 x 10^-4 = 1.45 x 10^-3 m^2

Change in magnetic field, ΔB = 95.5 - 50.5 = 45 mT = 45 x 10^-3 T

time, Δt = 0.165 second

induced emf

e = N x dФ/dt

where, dФ be the change in flux.

e = N x A x ΔB/Δt

e = 149 x 1.45 x 10^-3 x 45 x 10^-3 / 0.165

e = 0.058 V

4 0

3 years ago