Answer:
Step-by-step explanation:
Given Equation:
x^3- 4x^2 + 2x+ 10 = x^2 - 5x-3
which simplifies to
x^3- 5x^2 + 7x+ 13 = 0
Given one of the roots is x = 3x+2i, the conjugate is therefore x = 3-2i.
The product is real, (x-3+2i)(x-3-2i) = x^2-6x+13
The other root can therefore be obtained by long division
(x^3- 5x^2 + 7x+ 13)/(x^2-6x+13) = x+1, or x=-1
Therefore the three roots are:
{x=3-2i, x=3+2i, x=-1 }
If you want to calculate 5*(a-4) - 8*a = 55, you
have to do few steps to get to know the value of the a.
5*a - 20 - 8*a = 55
-3*a = 55 + 20
-3*a = 75 /(-3)
a = - 25
The correct result and the value of the a is -25.
The domain and the range are 0 ≤ ∅ ≤ 2π and -1 ≤ cos(∅) ≤ 1, respectively.
<h3>The domain and the range</h3>
The domain is the set of input values i.e. the ∅ values.
On the table, we can see that the ∅ value is from 0 to 2π.
This means that the domain is 0 ≤ ∅ ≤ 2π
On the other hand, the range is the set of output values i.e. the cos(∅) values.
On the table, we can see that the cos(∅) value is from -1 to 1.
This means that the range is -1 ≤ cos(∅) ≤ 1
Hence, the domain and the range are 0 ≤ ∅ ≤ 2π and -1 ≤ cos(∅) ≤ 1, respectively.
<h3>The points on a graph</h3>
See attachment 1
<h3>The graph of the function</h3>
See attachment 2
Read more about domain and range at:
brainly.com/question/2264373
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