For part A the choices are 25 and 34 and for part b it is 2 and 10

Mathematics

1 answer:

diamong [38]2 years ago

5 0

Answer:

Part A is 34

Part B is 2

Step-by-step explanation:

This question did provide some clues to answer this question. Every week, the area covered by the algae is multiplied by 2^1.

To find the area cover increase by the algae per day, the exponent should be divided by 7 since there are 7 days in a week. Hence, every day, the area covered by the algae multiplies by 2^(1/7). In other words, 1 day after the algae was spotted, the area is 12.5 * 2^(1/7), which answers part B.

10 days after the algae was spotted, the area covered by the algae is 12.5 * 2^[(1/7)*10] = 33.6475... , which rounds up to 34 and answers part A.

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PLEASE PLEASE HELP! Find the measure of APB^.

Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

$\angle CAT=\angle CBT=90^{\circ}$

Since angle BAT is equal to 65°, angle CAB has measure

$\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.$

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

$\angle CBA=\angle CAB=25^{\circ}$

The sum of the measures of all interior angles in triangle is always 180°, so

$\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}$

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

$x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}$