The linear equation that is perpendicular to the line x+3y=21 is:
y = 3*x - 6
<h3>How to find the equation of the line?</h3>
A general line in the slope-intercept form is written as:
y = m*x + b
Where m is the slope and b is the y-intercept.
Two linear equations are perpendicular if the product between the two slopes is equal to -1.
Rewriting the given line we can get:
x +3y = 21
3y = 21 - x
y = 21/3 - x/3
y = (-1/3)*x + 21/3
Then the slope is (-1/3), if our line is perpendicular to this one, then:
m*(-1/3) = -1
m = 3
our line is:
y = 3*x + b
To find the value of b, we use the fact that our line passes through (1, - 3)
-3 = 3*1 + b
-3 - 3 = b
-6 = b
The line is y = 3*x - 6
Learn more about linear equations:
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If from the negative to the positive side, count how many dots are in between and add together. So it is 6 units apart or 6 dots apart.
She was 22 when she had triplets
so if the triplets are 12 then just add
22+12=34
or when she had Mia she was 18
if Mia is 16 then add
18+16=34
Also, she had another child at 23
if the child is 11 then add
23+11=34
Hope it helps! :)
Jack can give three apples to 18 friends and have 2 left over
Answer:
(a) 12.96 ft²
(b) 21.5 in²
Step-by-step explanation:
(a) For the first diagram
Area of the shaded region (A) = Area of Tripezium- area of circle
A = [1/2(a+b)h]-[πr²]............... Equation 1
Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.
From the diagram,
Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.
Constant: π = 3.14
Substitute these values into equation 1
A = [12(15+6)/2]-(3.14×6²)
A = 126-113.04
A = 12.96 ft²
(b) For the second diagram,
Area of the shaded region (A') = Area of square- area of circle
A' = (L²)-(πr²)............. Equation 2
Where L = lenght of one side of the square, r = radius of the circle
From the diagram,
Given: L = 2r = (2×5) = 10 in, r = 5 in
Substitute these values into equation 2
A' = (10²)-(3.14×5²)
A' = 100-78.5
A = 21.5 in²
