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Rudik [331]
3 years ago
15

Can somebody help with this please

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

"D"

Step-by-step explanation:

just add the two functions

5x^2 - 8x^2 = -3x^2 etc

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Consider the quadratic equation. x^2=4x-5. How many solutions does the equation have?
Vesna [10]

x^2=4x-5
subtract 4x from both sides
x^2-4x=-5
add 5 to both sides
x^2-4x+5=0

input into quadratic formula which is x=\frac{-b+ \sqrt{b^2-4ac} }{2a} or \frac{-b- \sqrt{b^2-4ac} }{2a}

si ax^2+bx+c
so a=1
b=-4
c=5
input
\frac{-(-4)+ \sqrt{-4^2-4(1)(5)} }{2(1)}=\frac{4+ \sqrt{16-20} }{2(1)}=\frac{4+ \sqrt{-4} }{2}=\frac{4+ \sqrt{4} times \sqrt{-1} }{2} \frac{4+2 times  \sqrt{-1}  }{2}=  \frac{6 times  \sqrt{-1}  }{2}=3 times  \sqrt{-1} [\tex][\tex]\sqrt{-1} representeds by 'i' so solution is 3i

then if other way around then wyou would do
\frac{-(-4)- \sqrt{-4^2-4(1)(5)} }{2(1)}=\frac{4- \sqrt{16-20} }{2(1)}= \frac{4- \sqrt{-4} }{2} =\frac{4- \sqrt{4} times \sqrt{-1} }{2}= \frac{4-2 times \sqrt{-1} }{2}=\frac{2 \sqrt{-1} }{2}= \sqrt{-1} and [\tex]\sqrt{-1} [/tex] is represented by i


the solution is x=3i or i (i=\sqrt{-1})
but i is not real, it is imaginary so there are no real solution so the answer is C



3 0
3 years ago
Find the slope when given (2,3) (3,5) plz
maxonik [38]
(y2-y1)/(x2-x1)
=(5-3)/(3-2)
=2/1
=2

so the slope is 2
hope this helps !
5 0
3 years ago
Read 2 more answers
5x+y=-24 x+3y=-2<br>Substitution problem
seropon [69]

Answer: and Step-by-step explanation

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−5,1)(-5,1)

Equation Form:x=−5y=1x=-5y=1


6 0
4 years ago
What is the volume of the prism
Diano4ka-milaya [45]

Answer:

You need to include the prism, so then i can further help you :)

Step-by-step explanation:

6 0
2 years ago
Determine the x &amp; y intercepts for<br> -9y+ 37 = 8x.
lukranit [14]
X intercepts: (37/8,0)
y intercepts: (0,37/9)
3 0
3 years ago
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