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Usimov [2.4K]
3 years ago
8

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

x = 6

y = 3

Step-by-step explanation:

Give triangle is a right triangle.

By applying sine ratio in the given triangle,

sin(60)° = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}

x = 6

Now we take the cosine ratio in the given triangle,

cos(60)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{y}{x}

y = \frac{x}{2}

y = \frac{6}{2}=3

Therefore, x = 6 and y = 3 will be the answer.

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Hope you have a good day, Loves!

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3 years ago
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Find maximum points y=11^(6x-x²) solve using derivative
Darya [45]

Answer:

\boxed{\sf \ \ \ maximum \ is \ 11^9=2357947691 \ \ \ }

Step-by-step explanation:

hello

y = 11^{(6x-x^2)}=exp((6x-x^2)ln(11))

so to know the maximum to y we can check the maximum of

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f is derivable and f'(x)=6-2x

f'(x)=0 <=> x = 3

so the maximum is reached for x = 3

f(3)=18-9=9

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y = 11^9=2357947691

to be rigorous, we can write the variation table of y to show that there is only one maximum

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3 years ago
F(x)=-5x. g(x)=8x^2-5x-9. Find: (f*g) (x)
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Step-by-step explanation:

The quotient of x and 2 = x ÷ 2 = x/2

The product is the result of multiplying two or more other numbers

The sum is the result of adding two or more numbers

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3 years ago
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