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Usimov [2.4K]
3 years ago
8

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

x = 6

y = 3

Step-by-step explanation:

Give triangle is a right triangle.

By applying sine ratio in the given triangle,

sin(60)° = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}

x = 6

Now we take the cosine ratio in the given triangle,

cos(60)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{y}{x}

y = \frac{x}{2}

y = \frac{6}{2}=3

Therefore, x = 6 and y = 3 will be the answer.

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Solve the equation 4*e+2=1 (mod5)
otez555 [7]

Here's a way to do it.

Let 4e +2 = 5n +1 . . . . . . for some integer n

Then e = (5n -1)/4 = n + (n -1)/4

We want (n-1)/4 to be an integer, so let it be integer m.

... m = (n -1)/4

... 4m = n -1

... 4m +1 = n

Substituting this into our expression for e gives

... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1

e = 5m+1 for any integer m

4 0
3 years ago
What is 5m2- 15m- 200
vitfil [10]

Answer:

5(m + 5) (m - 8)

Step-by-step explanation:

5m2- 15m- 200

Start by pulling 5 out.

5(m^2 - 3m - 40)

We consider all factors of 40  

1    40

2   20

4    10

5     8

Based on the middle term we know that 5   and 8 are our best option.

5(m     5) (m     8)

We know the signs have to be one + and one -  because a - * - = + and + * + = +

Since 5 - 8 would give us -3 we know that our answer is

5(m + 5) (m - 8)

3 0
3 years ago
Algebra help needed. Overwhelmed with other papers. See attached
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

whitch answer how do you want us to answer

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3 years ago
Simplify.<br> (w^2 + 3w)-(w^2+5w-4<br><br> 8w-4<br> 2w^2 +8w-4<br> -2w+4<br> -2w
chubhunter [2.5K]

Answer:

-2w + 4

Step-by-step explanation:

Remove parenthesis because they make life semi-confusing but remember to distribute the negative: w^2 + 3w -w^2 - 5w + 4

Combine like terms: w^2 - w^2 cancel out ; 3w - 5w = -2w ; 4

-2w + 4

3 0
3 years ago
Round. each to the nearest tenth 10,061
lora16 [44]
10,060 would be the answer.
3 0
3 years ago
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