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lubasha [3.4K]
2 years ago
6

PRACTICE ANOTHER The administration of a large university wants to take a random sample to measure student opinion of a new food

service on campus. It plans to use a scale from 1 to 100, on which 1 is complete dissatisfaction and 100 is complete satisfaction. The administration knows from past experience with such questions that the standard deviation for the responses is going to be about 3, but it does not know what to expect for the mean. It wants to be almost sure that the sample mean is within plus or minus 1 point of the true population mean value. How large, n will the random sample have to be
Mathematics
1 answer:
Reil [10]2 years ago
3 0

Answer:

81 samples

Step-by-step explanation:

According to the empirical rule :

Possible values of the sample mean is within 3 standard deviations of the population mean :

μ ± 3 sd(x) ; sd(x) = standard deviation of sampling distribution.

3 * sd(x) = 1

sd(x) = 1/3

Recall:

Standard deviation of sampling distribution, sd(x)

sd(x) = σ / sqrt(n)

1/3 = 3 / sqrt(n)

Square both sides

1/9 = 9/n

Cross multiply :

n * 1 = 9 * 9

n = 81

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Answer:

=

$

518.01

Explanation:

compound interest formula $A = P*(1+R)^n#

P

=

$

400

,

r

=

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=

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Substituting the values, we get A =  

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⋅

(

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=

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From my alt account from, https://socratic.org/questions/how-much-would-400-invested-at-9-interest-compounded-continuously-be-worth-after

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