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sladkih [1.3K]
3 years ago
11

Go

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

two of the sides are 21 m long and one of the sides is 28 m long

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A container of medication holds 500 mL when full. The pharmacist has used 5/6 of the medication. How many milliliters are still
tankabanditka [31]
Is 5/6 in mL as well?
3 0
3 years ago
Chad ran a red light and hit another car. He decided to file a claim for damage
pochemuha

Answer:

Comprehensive deductible

Step-by-step explanation:

There is nothing called Premium deductible rather deductible determines how higher of lower a premium on a subject matter of insurance can be. Deductible is the amount with the insured have to bear at loss and any excess above the loss will be compensated by the insurance company.

Comprehensive deductible is the application to only to comprehensive insurance which was what Chad had on his motor vehicle. Comprehensive insurance covers majority of peril that happens to the insured vehicle. Therefore, comprehensive deductible is the deductible Chad has to bear himself before the insurance company take other losses upon theirself..

If he had $500 deductible on his car and total repair cost $700, then he will bear the $500 while the insurance company is entitled to pay only $200 as per policy statement.

6 0
3 years ago
Read 2 more answers
Which equation is equivalent to -2(2 − 2x) = 4 − 8(1 − x)
Kay [80]

Answer:

8 = 4x OR 0 = 4x

Step-by-step explanation:

I not %100 sure or it could be 0 = 4x

EITHERONE

6 0
3 years ago
Can someone answer both of these??
antiseptic1488 [7]

Answer:

The first graph is the last option (y=5/2z) the second graph is the first option (y=5/4z)

Step-by-step explanation:

Find the rise over run

4 0
4 years ago
Please explain how - calc ab - see attached photo
baherus [9]

Answer:

D

Step-by-step explanation:

Set up to different integrals that match the endpoints

so in our case it would look like

\int\limits^0_{-2} {x} \, dx +\int\limits^1_0 {x+1} \, dx

now it's just a matter of computing it

\int\limits^0_{-2} {x} \, dx =x^2\\0^2-(-2)^2=4\\\int\limits^1_0 {x+1} \, dx =\frac{x^2}{2}+x\\\frac{1}{2}+1-0=\frac{3}{2}\\\frac{3}{2}+4=\frac{11}{2}

4 0
3 years ago
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