Answer:
Wyzant
Question
Flying against the wind, an airplane travels 4200 km in 7 hours. Flying with the wind, the same plane travels 4000 km in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 1 vote
Let Va = the velocity of the airplane Let Vw = the velocity of the wind When flying with the wind: (Va+Vw)*(4 hours) = 4000 4Va + 4Vw = 4000 4Vw = 4000 - 4Va Vw = 1000 - Va When flying against the wind: (Va-Vw)*(7 hours) = 4200 km7Va - 7Vw = 4200 Substitute 1000-Va for Vw and solve for Va: 7Va - 7(1000-Va) = 4200 7Va -7000 + 7Va = 4200 14Va = 11200 Va = 800 km/hr Rate of wind: Vw = 1000 - Va = 1000 - 800 = 200 km/hour
More
Socratic
Question
Flying against the wind, an airplane travels 4500 in 5 hours. Flying with the wind, the same plane travels 4640 in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 0 votes
The speed of plane in still air is 1030 km/hr and wind
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
When dealing with an equation that only involves addition and subtraction ...you can solve it juat as it is witout using any special method same applied to equations tht involve only multiplication and division ... because they are an (inverse) of each other... hope it helps
Answer:
b. cos²3x - sin²3x = cos6x
if its wrong sorry
hope this helps you☺️☺️
Answer: 16 pi or ≈50.27
Explanation: Formula for a cylinder:
V = pi r ^2 h
V = pi (2)^2 4
V = 4 pi (4)
V = 16pi
Answer:
You put a equal sign or if its one equation then put a addition or subtraction sign etc.
Step-by-step explanation: