Answer:
a)
Speed at Equator = 463.97 meters per second
Centripetal Acceleration at Equator =
meters per second squared
b)
Speed at 30 degrees north of equator = 401.79 meters per second
Centripetal Acceleration at 30 degrees north of equator =
meters per second squared
Step-by-step explanation:
The formula is:

Where
v is speed
R is radius
T is time
and another formula for centripetal acceleration:

Now,
a)
at equator, the radius is radius of earth (given), time in seconds is
T = 24 * 60 * 60 = 86,400
THus,

Speed at Equator = 463.97 meters per second
Centripetal Acceleration:

Centripetal Acceleration at Equator =
meters per second squared
b)
At 30.0° north of the equator:

Now,
Speed = 
Speed at 30 degrees north of equator = 401.79 meters per second
Centripetal Acceleration:

Centripetal Acceleration at 30 degrees north of equator =
meters per second squared