Answer:
x = -5 y = -3
Step-by-step explanation:
-3x + 2y = 9
multiply the 2nd equation by 3 to set it up for elimination
3(x - 3y)= 3(4)
3x-9y = 12
so now combine both to add
-3x + 2y = 9
3x - 9y = 12
Adding both gives you
-7y = 21
divide both by -7 and you get
y = -3
and you substitute y back into equation to get x
x - 3 (-3) = 4 gives you
x + 9 = 4
x = 4 - 9
x = -5
Answer:
He and each of his sisters will recieve 1/4 of the pizza
Step-by-step explanation:
Answer:
Step-by-step explanation:
The radius of a circle is always half the radius.
Thus, in this case, the radius is (1/2)(34 in) = 17 in.
The "how far" question is answerable by finding the circumference of the wheel. The circumference, C, is found by calculating C = πd, where d is the diameter of the circle in question.
Here, C = (34 in)π, which comes out to 106.81 inches. The bike will move 106.81 inches forward if the wheel turns once.
If the wheel turns 5 times, the total distance traveled is 5 times the circumference, or 5(106.81 in) = 534.07 in.
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
The factor form for this will be (3x+1)(2x+1). Hope it help!
